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Perhaps beginners like me should not be doing a MIT course, but anyway,
how do you call a function in Python ?
Thanks
 one year ago
 one year ago
Perhaps beginners like me should not be doing a MIT course, but anyway, how do you call a function in Python ? Thanks
 one year ago
 one year ago

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Chris2332Best ResponseYou've already chosen the best response.0
By it's name? Not quite sure I understand the question!
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
Thanks, I forgot to define it first !
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
Suppose we have a function like this: def f(): #code here To call it, you would do f(). If the function takes arguments like the one below: def g(x, y, z): #code here Then you would do g(5, 3, 5), to correspond to the argument list. Note that if you're calling an instance method like the one defined below: class Teapot(object): def make_tea(self, amount): # code Make sure you don't pass 2 arguments. The self argument here is automatically provided. Example: myTP = Teapot() myTP.make_tea(5) # Notice that we don't pass the self argument in Should be a good crash course.
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
So, I put in a separate file and just f(args)
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
It's just that I'm trying to get to grips with defining and running a function using my Linux machine (just shell or python shell, no idle)
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
Because I'm doing L4 problem 1 functions and trying def a (x): return x + 1 then calling it with a(a(a(6)))
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
And of course that works now because previously I was calling it while still within the function, so got error (python shell) Thanks all
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
Additionally though I am not entirely sure what the above call is actually doing, presumably calling the function 'a' 3 times, which (again presumably) , as the function adds 1 to 'x', simply adds 1 to x 3 times with the value of x incrementing each time Perhaps now though I am sure.
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.0
Cracking open the a(a(a(6))), it looks like this: Call a with the argument (the result of Call a with the argument (the result of Call a with the argument 6)))
 one year ago

minimallinuxBest ResponseYou've already chosen the best response.1
So I was wrong, its returns 1, 1+1,2+1 then 3 + 6
 one year ago
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