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anonymous
 3 years ago
I was wondering if anyone could possibly help me with this math problem, I had passed algebra long ago, but I had this problem in my other memory test, which I had forgotten..
c^9 d^7/c^14 d^10
a > d^2/d^4
b > c5d3
c > d^3/c^5
d > c2d4
I'm not really sure how this website works, but credit or reward will be the one that is helpful towards me. Thanks.
anonymous
 3 years ago
I was wondering if anyone could possibly help me with this math problem, I had passed algebra long ago, but I had this problem in my other memory test, which I had forgotten.. c^9 d^7/c^14 d^10 a > d^2/d^4 b > c5d3 c > d^3/c^5 d > c2d4 I'm not really sure how this website works, but credit or reward will be the one that is helpful towards me. Thanks.

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AccessDenied
 3 years ago
Best ResponseYou've already chosen the best response.2\[ \large \frac{c^9 d^{7}}{c^{14} d^{10}} \] There are two properties we can use here: 1) Negative Exponents: \(\large a^{x} = \frac{1}{a^{x}} \) We may take a negative exponent over or under the fraction bar to get rid of the negative / turn it into a positive. 2) Multiplication of likebases: \(\large a^{x} a^{y} = a^{x + y} \) We can group together multiplication of likebases with this property, just adding together the exponents. Division is also possible if we use the first property with this one: \(\large \frac{a^{x}}{a^{y}} = a^{x}a^{y} = a^{xy}\)

AccessDenied
 3 years ago
Best ResponseYou've already chosen the best response.2So there are a number of ways to do this problem using some combination of those two properties. One that might be easier visually is to take everything to the numerator using the negative exponent property, add together the exponents of the likebases, and then put negative exponents back into the denominator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh.. ! I see what you did there. Thanks !

AccessDenied
 3 years ago
Best ResponseYou've already chosen the best response.2You're welcome. :)
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