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flyinglikeabird?
Group Title
Write the equation for the inequality shown on the graph. Use the form ax + by < c (Use the correct operator <, >, <, >. To type in a greater than or equal to or less than or equal to, just select the < or > sign and click on underline.)
 one year ago
 one year ago
flyinglikeabird? Group Title
Write the equation for the inequality shown on the graph. Use the form ax + by < c (Use the correct operator <, >, <, >. To type in a greater than or equal to or less than or equal to, just select the < or > sign and click on underline.)
 one year ago
 one year ago

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tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Start by writing the equality. Easy way is to take 2 points and get the equation of a line. Then it can be converted to the form indicated in your question. A great point to use is (0,0). Your second point can be anything else. But using (0,0) as one of the points will be easiest.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
If I were doing the problem, I'd start with the form y = mx + b because that is so easy to use and the intercept is very easy. You might want to find the slope. That's a really good start.
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Mmk, I think I got whatchu meant. Will try and figure it out. Thanks! (:
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
I'll stick with you on this if you want to go through it. You don't have to do the whole thing on your own. I'll guide you through it. The first and very easiest way to start with this particular problem is to find the intercept. At what value of y do you have for x=0? That will be your "b" and it will be a very easy "b".
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Sorry, I don't really understand what you are asking. You might have to knock it down to dumb level...D:
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Your equation is y = mx + b. If you look at the graph at find where x=0, what value of y do you have?
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Umm 0?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Yes. So, your new equation is y = mx. What is the slope?
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
2?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
You are close. You are going up 2 and over 1, but you are going over to the left, not the right, so your slope is 2.
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Ahh, right! Forgot about the left  right + thing.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
So, y = 2x. So, the format of the problem specifies 2x + y = 0, for the equality.
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Now just pick a point in the shaded area and plug it into the equation so that you can put in the correct < or > in addition to the = sign.
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Okay, so (1, 1)
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Good selection, so putting that into the equation, we would have 2(1) + (1) ? 0. Find the correct < or >.
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Its <
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Yes, very good. So your end expression is 2x + y < 0. You leave out the "=" because the line is dotted and is not part of the graph. It would have been part of the graph it was solid.
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
Right, okay. That all made sense. Thanks for the help. much appreciated. (:
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Good luck and have a great day.
 one year ago

flyinglikeabird? Group TitleBest ResponseYou've already chosen the best response.0
You too!
 one year ago
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