A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Solve (4x^2)(x^22x+2)<0
anonymous
 3 years ago
Solve (4x^2)(x^22x+2)<0

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(4x^2)(x^22x+2)<0 Let's study the equation. If (4  x^2) = 0, then 0 < 0 which isn't true. If (x^2  2x +2 ) = 0, then 0 < 0 which also isn't true. Now, let's look at (x^2  2x +2 ) Let's rewrite this equation (x1)^2 + 1 If you look at this equation, no matter what value of x you put in, the square will always make it positive (excluding complex numbers but I hope you don't have to deal with that here) What does that mean? It means that (x^22x+2)>0 and is a positive number. That means that (4x^2) must be less than 0. It must be a negative number. How do we figure that out? We solve this: 4x^2 < 0 If you graph this, you'll see that it's a parabola with it's vertex at (0,4) and it opens downwards. The line of the graph should be dashed which represents the points in this equation does not include the points on that line.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.