A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
4. The cost of a longdistance telephone call is given by the function
C(m) = 0.1m + 0.95
where m is the length of the call in minutes. Determine how long a phone call can be made for $5.95.
100 minutes
50 minutes
45 minutes
59 minutes
 2 years ago
4. The cost of a longdistance telephone call is given by the function C(m) = 0.1m + 0.95 where m is the length of the call in minutes. Determine how long a phone call can be made for $5.95. 100 minutes 50 minutes 45 minutes 59 minutes

This Question is Closed

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.15.95 = 0.1m + 0.95 solve for m

sarahlikewoe
 2 years ago
Best ResponseYou've already chosen the best response.0how do i do tht again ?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0when was your book written, 1976? who pays for long distance calls at ten cents a minute?

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.1subtract 0.95 from both sides

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0\[595=10m+95\] is a good start, work with pennies

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0subtract 95 divide by 10

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.15.95 = 0.1m +0.95 subtract 0.95 from both sides 5 = 0.1m divide by 0.1 (its like multiplying by 10) both sides m=50
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.