## monroe17 Group Title Find dy/dx by implicit differentation: 5+3x=sin(xy^7) 2 years ago 2 years ago

1. remnant

what have you got so far? do you know how to differentiate implicitly?

2. monroe17

I don't even know how to start.. My professor has a very strong accent and I was completely lost during the lecture today.

what is written xy power????

4. monroe17

$5+3x=\sin(xy^7)$

6. monroe17

I don't want the answer. I want to know how to do it.

7. remnant

If you want some help actually understanding implicit differentiation and not just an answer then check these out: http://www.khanacademy.org/math/calculus/differential-calculus/v/implicit-differentiation http://tutorial.math.lamar.edu/Classes/CalcI/ImplicitDIff.aspx

8. monroe17

thank you!

9. remnant

i find Paul's Online Notes and Khan Academy to be the best at teaching things online :) goodluck :)

5+3x=sin(xy7) taking derivative on both sides 3=cos(xy7)(x.d/dx(y7).d/dx(y))+y) 3=cos(xy7)(x7y6.dy/dx+y) 3-ycos(xy7)=cos(xy7)(x7y6.dy/dx) dy/dx=3-ycos(xy7)/cos(xy7)7xy6