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monroe17

  • 3 years ago

Find dy/dx by implicit differentation: 5+3x=sin(xy^7)

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  1. remnant
    • 3 years ago
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    what have you got so far? do you know how to differentiate implicitly?

  2. monroe17
    • 3 years ago
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    I don't even know how to start.. My professor has a very strong accent and I was completely lost during the lecture today.

  3. aatifsayyad
    • 3 years ago
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    what is written xy power????

  4. monroe17
    • 3 years ago
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    \[5+3x=\sin(xy^7)\]

  5. aatifsayyad
    • 3 years ago
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    ok....just wait for answer

  6. monroe17
    • 3 years ago
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    I don't want the answer. I want to know how to do it.

  7. remnant
    • 3 years ago
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    If you want some help actually understanding implicit differentiation and not just an answer then check these out: http://www.khanacademy.org/math/calculus/differential-calculus/v/implicit-differentiation http://tutorial.math.lamar.edu/Classes/CalcI/ImplicitDIff.aspx

  8. monroe17
    • 3 years ago
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    thank you!

  9. remnant
    • 3 years ago
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    i find Paul's Online Notes and Khan Academy to be the best at teaching things online :) goodluck :)

  10. aatifsayyad
    • 3 years ago
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    5+3x=sin(xy7) taking derivative on both sides 3=cos(xy7)(x.d/dx(y7).d/dx(y))+y) 3=cos(xy7)(x7y6.dy/dx+y) 3-ycos(xy7)=cos(xy7)(x7y6.dy/dx) dy/dx=3-ycos(xy7)/cos(xy7)7xy6

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