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monroe17
 3 years ago
Find dy/dx by implicit differentation:
5+3x=sin(xy^7)
monroe17
 3 years ago
Find dy/dx by implicit differentation: 5+3x=sin(xy^7)

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remnant
 3 years ago
Best ResponseYou've already chosen the best response.1what have you got so far? do you know how to differentiate implicitly?

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.1I don't even know how to start.. My professor has a very strong accent and I was completely lost during the lecture today.

aatifsayyad
 3 years ago
Best ResponseYou've already chosen the best response.0what is written xy power????

aatifsayyad
 3 years ago
Best ResponseYou've already chosen the best response.0ok....just wait for answer

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.1I don't want the answer. I want to know how to do it.

remnant
 3 years ago
Best ResponseYou've already chosen the best response.1If you want some help actually understanding implicit differentiation and not just an answer then check these out: http://www.khanacademy.org/math/calculus/differentialcalculus/v/implicitdifferentiation http://tutorial.math.lamar.edu/Classes/CalcI/ImplicitDIff.aspx

remnant
 3 years ago
Best ResponseYou've already chosen the best response.1i find Paul's Online Notes and Khan Academy to be the best at teaching things online :) goodluck :)

aatifsayyad
 3 years ago
Best ResponseYou've already chosen the best response.05+3x=sin(xy7) taking derivative on both sides 3=cos(xy7)(x.d/dx(y7).d/dx(y))+y) 3=cos(xy7)(x7y6.dy/dx+y) 3ycos(xy7)=cos(xy7)(x7y6.dy/dx) dy/dx=3ycos(xy7)/cos(xy7)7xy6
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