anonymous
  • anonymous
y=d/dx integralcosx to 0 t/(1+t)dt
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[d/dx \int\limits_{0}^{cosx} \frac{ t }{ 1+t } dt\]
anonymous
  • anonymous
\[\frac{cosx}{1+cosx}\]
anonymous
  • anonymous
how did u do it?

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anonymous
  • anonymous
@Outkast3r09 I think u made a miss take in your first step (While u made the integral)
anonymous
  • anonymous
the derivative of an integral is simply the integral itself with the variables in other words ... integrals and derivatives cancel eachother out
anonymous
  • anonymous
\[\frac{cosx}{1+cosx} \]is your answer
anonymous
  • anonymous
It should be\[\cos(x)-\ln(1+\cos(x))\]
anonymous
  • anonymous
|dw:1349804491261:dw|
anonymous
  • anonymous
Now take the derivative
anonymous
  • anonymous
it shouldn't be anything @ zekarias
anonymous
  • anonymous
@zekarias ... you don't need to do anything
anonymous
  • anonymous
What u get finally?
anonymous
  • anonymous
so the answer is just cosx/1+cosx ?
anonymous
  • anonymous
yes
anonymous
  • anonymous
thanks,wolfram gives me the same answer,just wanted to make sure how it was done
anonymous
  • anonymous
it's just simply knowing how an integral work... there is a lot of work to do it zekarias way but if you just know that the the derivative on an integral will bring you back to the f(x) within the integral... that's all you need to know(This works anytime the lower limit is some real number) because if you think about it.... |dw:1349804918350:dw| if you take the derivative of f(n)... you'll always get zero
anonymous
  • anonymous
oh thanks alot sweedy :)

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