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kryptonBest ResponseYou've already chosen the best response.1
\[d/dx \int\limits_{0}^{cosx} \frac{ t }{ 1+t } dt\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
\[\frac{cosx}{1+cosx}\]
 one year ago

ZekariasBest ResponseYou've already chosen the best response.0
@Outkast3r09 I think u made a miss take in your first step (While u made the integral)
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
the derivative of an integral is simply the integral itself with the variables in other words ... integrals and derivatives cancel eachother out
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
\[\frac{cosx}{1+cosx} \]is your answer
 one year ago

ZekariasBest ResponseYou've already chosen the best response.0
It should be\[\cos(x)\ln(1+\cos(x))\]
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
dw:1349804491261:dw
 one year ago

ZekariasBest ResponseYou've already chosen the best response.0
Now take the derivative
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
it shouldn't be anything @ zekarias
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
@zekarias ... you don't need to do anything
 one year ago

kryptonBest ResponseYou've already chosen the best response.1
so the answer is just cosx/1+cosx ?
 one year ago

kryptonBest ResponseYou've already chosen the best response.1
thanks,wolfram gives me the same answer,just wanted to make sure how it was done
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.1
it's just simply knowing how an integral work... there is a lot of work to do it zekarias way but if you just know that the the derivative on an integral will bring you back to the f(x) within the integral... that's all you need to know(This works anytime the lower limit is some real number) because if you think about it.... dw:1349804918350:dw if you take the derivative of f(n)... you'll always get zero
 one year ago

kryptonBest ResponseYou've already chosen the best response.1
oh thanks alot sweedy :)
 one year ago
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