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y=d/dx integralcosx to 0 t/(1+t)dt

Mathematics
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\[d/dx \int\limits_{0}^{cosx} \frac{ t }{ 1+t } dt\]
\[\frac{cosx}{1+cosx}\]
how did u do it?

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Other answers:

@Outkast3r09 I think u made a miss take in your first step (While u made the integral)
the derivative of an integral is simply the integral itself with the variables in other words ... integrals and derivatives cancel eachother out
\[\frac{cosx}{1+cosx} \]is your answer
It should be\[\cos(x)-\ln(1+\cos(x))\]
|dw:1349804491261:dw|
Now take the derivative
it shouldn't be anything @ zekarias
@zekarias ... you don't need to do anything
What u get finally?
so the answer is just cosx/1+cosx ?
yes
thanks,wolfram gives me the same answer,just wanted to make sure how it was done
it's just simply knowing how an integral work... there is a lot of work to do it zekarias way but if you just know that the the derivative on an integral will bring you back to the f(x) within the integral... that's all you need to know(This works anytime the lower limit is some real number) because if you think about it.... |dw:1349804918350:dw| if you take the derivative of f(n)... you'll always get zero
oh thanks alot sweedy :)

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