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helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \large 3\sqrt{2x}+x\sqrt{8x}5\sqrt{18x} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1first \[ \large \sqrt{8x}=\sqrt{2\cdot4x}=2\sqrt{2x} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \large \sqrt{18x}=\sqrt{2\cdot9x}=3\sqrt{2x} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1plug in the main expresion.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \large 3\sqrt{2x}+x\sqrt{8x}5\sqrt{18x}= \] \[ \large 3\sqrt{2x}+x[2\sqrt{2x}]5[3\sqrt{2x}]= 3\sqrt{2x}+2x\sqrt{2x}15\sqrt{2x} \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1now add/substract like terms

kiamonstaa
 2 years ago
Best ResponseYou've already chosen the best response.0is that it or am i missing something?

kiamonstaa
 2 years ago
Best ResponseYou've already chosen the best response.0\[12\sqrt{2x}+2x \sqrt{2x}\]

kiamonstaa
 2 years ago
Best ResponseYou've already chosen the best response.0oh. ha nvm i got it.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \large =12\sqrt{2x}+2x\sqrt{2x}=(2x12)\sqrt{2x} \]

marcoduuuh
 2 years ago
Best ResponseYou've already chosen the best response.0Which would be my answer. That's the final one without all the work. :p
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