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kiamonstaa Group Title

3√(2x)+x√(8x)-5√(18x)

  • one year ago
  • one year ago

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  1. kiamonstaa Group Title
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    show all work.

    • one year ago
  2. helder_edwin Group Title
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    \[ \large 3\sqrt{2x}+x\sqrt{8x}-5\sqrt{18x} \]

    • one year ago
  3. marcoduuuh Group Title
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    -12√2x+2x√2x

    • one year ago
  4. helder_edwin Group Title
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    first \[ \large \sqrt{8x}=\sqrt{2\cdot4x}=2\sqrt{2x} \]

    • one year ago
  5. helder_edwin Group Title
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    \[ \large \sqrt{18x}=\sqrt{2\cdot9x}=3\sqrt{2x} \]

    • one year ago
  6. kiamonstaa Group Title
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    okay what's next?

    • one year ago
  7. helder_edwin Group Title
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    plug in the main expresion.

    • one year ago
  8. helder_edwin Group Title
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    \[ \large 3\sqrt{2x}+x\sqrt{8x}-5\sqrt{18x}= \] \[ \large 3\sqrt{2x}+x[2\sqrt{2x}]-5[3\sqrt{2x}]= 3\sqrt{2x}+2x\sqrt{2x}-15\sqrt{2x} \]

    • one year ago
  9. helder_edwin Group Title
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    now add/substract like terms

    • one year ago
  10. kiamonstaa Group Title
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    ohh.....okay thanks

    • one year ago
  11. helder_edwin Group Title
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    u r welcome

    • one year ago
  12. kiamonstaa Group Title
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    is that it or am i missing something?

    • one year ago
  13. helder_edwin Group Title
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    what did u get?

    • one year ago
  14. kiamonstaa Group Title
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    \[12\sqrt{2x}+2x \sqrt{2x}\]

    • one year ago
  15. kiamonstaa Group Title
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    oh. ha nvm i got it.

    • one year ago
  16. helder_edwin Group Title
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    \[ \large =-12\sqrt{2x}+2x\sqrt{2x}=(2x-12)\sqrt{2x} \]

    • one year ago
  17. kiamonstaa Group Title
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    ohhh.

    • one year ago
  18. marcoduuuh Group Title
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    Which would be my answer. That's the final one without all the work. :p

    • one year ago
  19. kiamonstaa Group Title
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    lol yeaa

    • one year ago
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