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helder_edwinBest ResponseYou've already chosen the best response.1
\[ \large 3\sqrt{2x}+x\sqrt{8x}5\sqrt{18x} \]
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
first \[ \large \sqrt{8x}=\sqrt{2\cdot4x}=2\sqrt{2x} \]
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
\[ \large \sqrt{18x}=\sqrt{2\cdot9x}=3\sqrt{2x} \]
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
plug in the main expresion.
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
\[ \large 3\sqrt{2x}+x\sqrt{8x}5\sqrt{18x}= \] \[ \large 3\sqrt{2x}+x[2\sqrt{2x}]5[3\sqrt{2x}]= 3\sqrt{2x}+2x\sqrt{2x}15\sqrt{2x} \]
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
now add/substract like terms
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
ohh.....okay thanks
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
is that it or am i missing something?
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
\[12\sqrt{2x}+2x \sqrt{2x}\]
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
oh. ha nvm i got it.
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
\[ \large =12\sqrt{2x}+2x\sqrt{2x}=(2x12)\sqrt{2x} \]
 one year ago

marcoduuuhBest ResponseYou've already chosen the best response.0
Which would be my answer. That's the final one without all the work. :p
 one year ago
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