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cathyangs
 3 years ago
Using each of the digits 2, 3, 4, 6, 7, and 8 exactly once, construct two 3digit integers M and N so that MN is positive and is a small as possible. Compute MN.
The smallest MN I found was 39. Anyone?
cathyangs
 3 years ago
Using each of the digits 2, 3, 4, 6, 7, and 8 exactly once, construct two 3digit integers M and N so that MN is positive and is a small as possible. Compute MN. The smallest MN I found was 39. Anyone?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.039 was the lowest I found as well

cathyangs
 3 years ago
Best ResponseYou've already chosen the best response.0I bet there's a mathematical way to figure out the smallest MN without knowing M or N, or something. >:( I never know with this questions if there's something wrong with my answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Or cant we repeat digit for both M and N

cathyangs
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, you can't repeat digits.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And there is a mathematical way to do it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let the first number "M" be = abc =a*100+b*10+c And the other number "N"be =a'b'c' = a'*100+b'*100+c' Then, MN=(a*100+b*10+c)(a'*100+b'*10+c') =(aa')*100+(bb')*100+(cc')

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, MN to be minimum...... aa' must be positive smallest number (FIRST priority) bb' must be smallest (Second priority) cc' must be smallest (Third priority)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, aa'=1 when a=4 and b=3 bb'=6 when b=2 and b'=6 cc'=1 when c=6 and c'=7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thus, Smallest MN=1*100+(6)*10+(1)=39
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