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Solve for x.

sorry didi i cant read that

(n-3)(n+4) = n^2 - 2

n is the integer.

\[(x-3)(x+4)=x^2-2\]

Better?

X is the integer.

yes better

x^2-10=x^2 ??

don't forget ur middle term of the FOIL on the left, then won't the x^2 subtract off...

Yes but the x^2's just cancel out.

x-10 ?

x-10 = 0, so x = ???

10

bingo!!

awesome...thank u