Solve using a system of equations: There is a collection of nickels and dimes worth $3.30. There are 42 coins in all. How many are there of each kind?

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Solve using a system of equations: There is a collection of nickels and dimes worth $3.30. There are 42 coins in all. How many are there of each kind?

Mathematics
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5n + 10d = 330 n + d = 42
n is the number of nickels and d is the number of dimes.
so you gotta use the second equation to solve for d

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Other answers:

or n, but i would do d
so what does d equal?
D=576
no, what you gotta do it find out what d is compared to n. so it's n + d = 42. what you do with that is subtract n from both sides to get d = 42 - n
and then you can substitute 42 - n for d in the first equation
so 5n + 10d = 330 would be 5n + 10(42 - n) = 330. is this making sense?
Yes, but we have to have a system of equations
the first thing i posted was our system of equations
now we're solving it
Oh right sorry
so do you know what to do from there? from 5n + 10(42 - n) = 330?
ok
so just distribute and then solve from there?
yea, distribute the 10 into the parentheses and then solve for n and once you know how many nickels there are, just substitute that for n in the second equation and solve for d
i get a negative
|dw:1349754629184:dw|
does that make sense?
yes i see were i made my mistake i forgot the negative sign
so now we know that 18 + d = 42 and we can solve for d
right plug in 18 in the n part
yup, so how many dimes are there?
there's 24
yep :) 24 dimes and 18 nickels

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