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Razial
Group Title
H5P1 ZEROOFFSET AMPLIFIER
In many amplifiers, we use dual power supplies so we can obtain a 0V offset at the output, that is, the DC operating point at the output is 0V. An example amplifier circuit that can achieve this is shown below.
In this circuit, VS+=1.0V, VS−=−1.0V, and the MOSFET parameters are K=1 mAV2 and VT=0.5V.
what formulas do i need to find Vin (while operating in saturation), RL, and max Vin (while still in saturation)
 one year ago
 one year ago
Razial Group Title
H5P1 ZEROOFFSET AMPLIFIER In many amplifiers, we use dual power supplies so we can obtain a 0V offset at the output, that is, the DC operating point at the output is 0V. An example amplifier circuit that can achieve this is shown below. In this circuit, VS+=1.0V, VS−=−1.0V, and the MOSFET parameters are K=1 mAV2 and VT=0.5V. what formulas do i need to find Vin (while operating in saturation), RL, and max Vin (while still in saturation)
 one year ago
 one year ago

This Question is Open

akash97 Group TitleBest ResponseYou've already chosen the best response.1
vIN = 0.5 VOLT & RL=8000 ohm
 one year ago

Razial Group TitleBest ResponseYou've already chosen the best response.0
so i ask for formula's yet i get answers... great job... helps me get the right answer... doesn't that i would like to know the equation's...
 one year ago

akash97 Group TitleBest ResponseYou've already chosen the best response.1
0.093 FOR 3rd que.......
 one year ago

Srikanth_Gangula Group TitleBest ResponseYou've already chosen the best response.0
HI Raizial!!! Here's the way to get solution Actually in finding valid Operating ranges \[V0 = [1 + \sqrt{1+2*K*RL*Vs} ] \div KRL\] In the above formula Vs= applied voltage across RL and Drain to Source( i.e Vds).. \[Vs=ids∗RL+Vds(or)Vs=ids∗RL+V0\] But in given problem , by applying KVL to output loop we get \[Vds+idsRL=Vs+(−Vs−)\] \[Vds+ids∗RL=1−(−1)=2\] So in finding V0 substitute\[Vs=2 \] (NOT 1) And we know Valid maximum input range is \[Vgs = V0 + Vthershold\] Applying KVL to input loop \[Vin=Vgs+Vs−\] Substitue the value ...You will get it !!!!!! Cheers!!!!
 one year ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
the above answer are correct but i need all three formula
 one year ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
Solve the previous two results for iDS. You will get a quadratic equation, and you will have to choose the correct root: make sure that iDS=0 when vIN=VT. What is your solution for iDS?
 one year ago

akash97 Group TitleBest ResponseYou've already chosen the best response.1
Actually in finding valid Operating ranges \[V0 = [1 + \sqrt{1+2*K*RL*Vs} ] \div KRL\] In the above formula Vs= applied voltage across RL and Drain to Source( i.e Vds).. \[Vs=ids∗RL+Vds(or)Vs=ids∗RL+V0\] But in given problem , by applying KVL to output loop we get \[Vds+idsRL=Vs+(−Vs−)\] \[Vds+ids∗RL=1−(−1)=2\] So in finding V0 substitute\[Vs=2 \] (NOT 1) And we know Valid maximum input range is \[Vgs = V0 + Vthershold\] Applying KVL to input loop \[Vin=Vgs+Vs−\] Substitue the value ...You will get it !!!!!! Cheers!!!!
 one year ago
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