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anonymous
 3 years ago
Where does the equation for simple pendulum motion come from? \[T=2\pi \sqrt{\frac{ l }{ g }}\] where T is period, l is string length, g is acc. due to gravity
anonymous
 3 years ago
Where does the equation for simple pendulum motion come from? \[T=2\pi \sqrt{\frac{ l }{ g }}\] where T is period, l is string length, g is acc. due to gravity

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0write down the equation of motion for pendulum

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349777134567:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why is the mg force not straight down?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry...mg is straight down only

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does it help u in finding the time period?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I want to know how the formula is derived...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know write down the equation of motion along the tangent... m( a_t) = mg sin(theta) a_ttangential acc

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0net force along tangent is mg sin (theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now v_tangential= r ( angular vel)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0differentiate it a_tangential= r(angular acc)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0r is the length of pendulum in this case

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now substitute a_tangential into m( a_t) = mg sin(theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0m(r*angular_acc) = m(sin(theta))

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0m ( l(angular acc))= mg sin(theta)....l=r= length of pendulum

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now l(angular acc))= g sin(theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where did the l come from?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0l=r=length of pendulum...pendulum is like bob is moving in a circle pivoted at centre

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh right... l = r. I forgot about that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now acceleration = g/l sin(theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0equation of SHM is a=  w^2 x then time period T= 2 pi/w

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I havent learnt SHM yet. whats w?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0w(omega)angular frequency acceleration = g/l sin(theta) for small theta acceleration = g/l (theta) sin(theta)= theta

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u know wave... omega= 2 pi (nu)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we say SHM is a periodic motion in which acceleration is directed towards a fixed point which is called equilibrium point.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok. I know the basics of it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok.. so acceleration = g/l (theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now compare this with a=  w^2 x where x is the displacement from fixed point

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so for small angle x = theta

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so acceleration and displacement are in opposite direction

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here theta is x.... for small angle sin(theta)= theta

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so in the case of pendulum angular displacement and angular acceleration are in opposite direction

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0write six in the form a power series sin x= x  x^3/3! + x^5/5!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so for small x sin x =x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0neglect higher order terms

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we have acceleration = g/l (theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I forgot what w is equal to

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0w= angular frequency= 2 pi( frequency)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0T= (2 pi)/ (2 pi( frequency))

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so where does the √ come in?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0w^2= g/l so what will be w?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so u got the time period.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I see one problem though... this will only be accurate with small angles right?
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