A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
If a mass of 2.0 kg is lifted through a height of 5.0 m, what force does it require to lift it at constant speed?
 2 years ago
If a mass of 2.0 kg is lifted through a height of 5.0 m, what force does it require to lift it at constant speed?

This Question is Closed

apple_pi
 2 years ago
Best ResponseYou've already chosen the best response.2Doesn't matter how high its lifted. The gravitational force experience = mass * acc. due to gravity. To balance this, an equal force in the opposite direction is required. So first calculate the gravitational force

amishra
 2 years ago
Best ResponseYou've already chosen the best response.0Gravitational force is 9.81 m/s^2 ? If so, Then we just use f=ma like F= 2*9.81 ? Is this correct?

apple_pi
 2 years ago
Best ResponseYou've already chosen the best response.2Wait... your question is what force is needed to keep it stationary or at constant speed. If stationary...do what I told you If constant speed, you need a net force of 0

apple_pi
 2 years ago
Best ResponseYou've already chosen the best response.2but yeah that's correct

amishra
 2 years ago
Best ResponseYou've already chosen the best response.0Wait, what force is needed to lift the object, assuming that we are moving at constant speed. So the force should come out to be negative right?

apple_pi
 2 years ago
Best ResponseYou've already chosen the best response.2Lift the object at constant speed..? Force is a vector unit so depending on which direction you put it could be pos or neg

amishra
 2 years ago
Best ResponseYou've already chosen the best response.0That's the question :/ Okay, thank you so much! :D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.