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Use the three steps to solve the problem. Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old as the son. How old is each now? {son is yrs., father is yrs.}

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Let the present age of son be x and the age of father be y. Can u tell me what was the age of the father two yrs ago?
no i dont know i am srry
Subtract 2 from the present age y.

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Other answers:

so it would be 2-y*4 right?
hmm no. The age of father two yrs ago is y-2. And the son,s is x-2. Since it is given that the father's age was 4 times the age of son y-2=4(x-2). Getting it?
Is it confusing? If so plz ask.
yes it's confusing
How old are u nw?
what was ur age before two yrs?
U subtracted to frm ur present age to find the age bfore 2 yrs. right?I assumed father's present age to be y. then his age before two yrs wud have been y-2. Is is it clear?
The age of the son bfore two yrs wud hav been x-2. Getting it?
sorry? isn't t clear?
it is
Since it is given that the age of the father was 4 times the son's age y-2=4(x-2)
Getting it?
What will be the age of the father after three years?
yup right:)
What will be the age of the son?
Since it is given that the father's age will be three times of the age of the son y+3=3(x+3) getting it?
So u hav two eqns y-2=4(x-2) y+3=3(x+3) Can u find x and y?
y-2=4x-8 y+3=3x=9
y-2=4x-8 y+3=3x+9 ya right:). Nw solve these equations to find x and y. can u do it?
y-2=4x-8 what do u get when u add 2 to both sides?
y-2+2=4x-8+2 y=4x-6
y+3=3x+9 What do u get when u subtract 3 from both of the sides?
hmm no. y+3-3=3x+9-3 y=3x+6 Getting it?
So u have two eqns y=4x-6 y=3x+6. Since both 4x-6 and 3x+6 are equal to y you can equate them. 4x-6=3x+6 Can u find x nw?
hmm no. 1.Add 6 both sides 2.Subtract 3x both sides. What do u get nw?
That is vat u get in left hand side. What do u get in ur right hand side?
@robtobey can u help me?
Solve the following for f and s, the father's and son's current age respectively.\[\left\{\frac{f-2}{s-2}=4,\frac{f+3}{s+3}\text{=}3\right\}\]Can you solve the above for f and s?
idk i dont know how to do it
Is the following easier?\[\{f-2=4(s-2),f+3=3(s+3)\}\]
i dont know this is all confusing to me
focus on the equation on the left. f - 2 = 4 (s - 2) Multiply out the RHS f - 2 = 4 s - 8 Move -2 to the RHS. f = 4 s - 8 + 2 Add -8 and +2 f = 4 s -6 Replace f in the second equation with 4 s -6 f + 3 = 3 (s + 3) (4 s -6) + 3 = 3 (s + 3) Can you solve the above for s and get a number?
son is 7
I have to log off now. The answer is\[\{f=42,s=12\} \] You should verify the answer yourself.

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