## kaiteDID Group Title Use the three steps to solve the problem. Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old as the son. How old is each now? {son is yrs., father is yrs.} one year ago one year ago

1. ajprincess Group Title

Let the present age of son be x and the age of father be y. Can u tell me what was the age of the father two yrs ago?

2. kaiteDID Group Title

no i dont know i am srry

3. ajprincess Group Title

Subtract 2 from the present age y.

4. kaiteDID Group Title

so it would be 2-y*4 right?

5. ajprincess Group Title

hmm no. The age of father two yrs ago is y-2. And the son,s is x-2. Since it is given that the father's age was 4 times the age of son y-2=4(x-2). Getting it?

6. kaiteDID Group Title

kinda

7. ajprincess Group Title

Is it confusing? If so plz ask.

8. kaiteDID Group Title

yes it's confusing

9. ajprincess Group Title

How old are u nw?

10. ajprincess Group Title

what was ur age before two yrs?

11. ajprincess Group Title

U subtracted to frm ur present age to find the age bfore 2 yrs. right?I assumed father's present age to be y. then his age before two yrs wud have been y-2. Is is it clear?

12. kaiteDID Group Title

yes

13. ajprincess Group Title

The age of the son bfore two yrs wud hav been x-2. Getting it?

14. kaiteDID Group Title

mmhhh

15. ajprincess Group Title

sorry? isn't t clear?

16. kaiteDID Group Title

it is

17. ajprincess Group Title

Since it is given that the age of the father was 4 times the son's age y-2=4(x-2)

18. ajprincess Group Title

Getting it?

19. kaiteDID Group Title

yes

20. ajprincess Group Title

What will be the age of the father after three years?

21. kaiteDID Group Title

y+3

22. ajprincess Group Title

yup right:)

23. ajprincess Group Title

What will be the age of the son?

24. kaiteDID Group Title

x+3

25. ajprincess Group Title

Since it is given that the father's age will be three times of the age of the son y+3=3(x+3) getting it?

26. kaiteDID Group Title

okay

27. ajprincess Group Title

So u hav two eqns y-2=4(x-2) y+3=3(x+3) Can u find x and y?

28. kaiteDID Group Title

y-2=4x-8 y+3=3x=9

29. ajprincess Group Title

y-2=4x-8 y+3=3x+9 ya right:). Nw solve these equations to find x and y. can u do it?

30. kaiteDID Group Title

idk

31. ajprincess Group Title

y-2=4x-8 what do u get when u add 2 to both sides?

32. kaiteDID Group Title

10

33. ajprincess Group Title

y-2+2=4x-8+2 y=4x-6

34. ajprincess Group Title

y+3=3x+9 What do u get when u subtract 3 from both of the sides?

35. kaiteDID Group Title

12

36. ajprincess Group Title

hmm no. y+3-3=3x+9-3 y=3x+6 Getting it?

37. kaiteDID Group Title

yes

38. ajprincess Group Title

So u have two eqns y=4x-6 y=3x+6. Since both 4x-6 and 3x+6 are equal to y you can equate them. 4x-6=3x+6 Can u find x nw?

39. kaiteDID Group Title

10

40. ajprincess Group Title

hmm no. 1.Add 6 both sides 2.Subtract 3x both sides. What do u get nw?

41. kaiteDID Group Title

1x

42. ajprincess Group Title

That is vat u get in left hand side. What do u get in ur right hand side?

43. kaiteDID Group Title

0

44. kaiteDID Group Title

@robtobey can u help me?

45. robtobey Group Title

Solve the following for f and s, the father's and son's current age respectively.$\left\{\frac{f-2}{s-2}=4,\frac{f+3}{s+3}\text{=}3\right\}$Can you solve the above for f and s?

46. kaiteDID Group Title

idk i dont know how to do it

47. robtobey Group Title

Is the following easier?$\{f-2=4(s-2),f+3=3(s+3)\}$

48. kaiteDID Group Title

i dont know this is all confusing to me

49. robtobey Group Title

focus on the equation on the left. f - 2 = 4 (s - 2) Multiply out the RHS f - 2 = 4 s - 8 Move -2 to the RHS. f = 4 s - 8 + 2 Add -8 and +2 f = 4 s -6 Replace f in the second equation with 4 s -6 f + 3 = 3 (s + 3) (4 s -6) + 3 = 3 (s + 3) Can you solve the above for s and get a number?

50. kaiteDID Group Title

son is 7

51. robtobey Group Title

I have to log off now. The answer is$\{f=42,s=12\}$ You should verify the answer yourself.

52. kaiteDID Group Title

okay