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find the lim (x+1/x) as x tends to 0.and sketch a graph to support for answer.
 one year ago
 one year ago
find the lim (x+1/x) as x tends to 0.and sketch a graph to support for answer.
 one year ago
 one year ago

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2leBest ResponseYou've already chosen the best response.1
\[lim_{x \rightarrow 0}(x+\frac{1}{x})=lim_{x \rightarrow 0}(\frac{x^2+1}{x})\] From here you can see that the function gets larger and larger as x approaches 0 from the left and the right.dw:1349841452926:dw also, if you look at \[lim_{x \rightarrow \infty}(\frac{x^2+1}{x})=2\] \[lim_{x \rightarrow \infty}(\frac{x^2+1}{x})=2\]from l'Hopital's rule
 one year ago

pastaBest ResponseYou've already chosen the best response.0
as x tends to infinity the function is undefined as far as i know
 one year ago

adi171Best ResponseYou've already chosen the best response.0
then the x^2 cancels out.....the eq left is 1/x^2...... now when x approaches 0 the eq. approaches infinity,...!!1 so infinity is the ans
 one year ago

adi171Best ResponseYou've already chosen the best response.0
graph is this and its correct
 one year ago

adi171Best ResponseYou've already chosen the best response.0
range of the grph is (infinity , 2] union [2,infinity)
 one year ago

pastaBest ResponseYou've already chosen the best response.0
@adi171 there is no way i can use l 'HOpitals rule becoz the function gives 1/0 not 0/0 OR infnty/infnty.
 one year ago

pastaBest ResponseYou've already chosen the best response.0
when i use the rule my derivative is 2x which gives the answer 0.HOW ARE YOU differentiating 2x/1 which is actualy the derivative .and it does not work for the rule on this case
 one year ago

pastaBest ResponseYou've already chosen the best response.0
you are finding the minimum and maximum points of this graph. as x tends to inifinity the function tends to infinity .and AS X tends to 0 the function is undefined(see the attached graph)
 one year ago
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