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sqrt x+10 = x-2

Mathematics
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\[\sqrt{x+10}=x-2\]
you first need to get rid of the radical.
so square both sides.

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Other answers:

ok
so you should have x+10 = x^2-4x-4 ?
now move your terms all to one side and set it equal to 0 and factor or use the quadratic to solve for x
ok
actualy... i typoed.. it should be \[x+10=x^{2}-4x+4\]
ok i was confused trying to work that out
and the only reason i move to the right is cause I dont want to multiply by a negative 1.
\[x ^{2}-5x-6=0\]
you know how to factor or do the quadratic?
i have my text book here, these confuse me so much
ok. i would factor this. so you set up parens.. ( )( ) right? fill them with (x )(x ). now we are looking for 2 numbers that multiply to 6 and add to -5
so 2 and 3 seem to work nice.. but they are not gonna get us to where we want because of the negative 5. so we try 1 and 6. (x 1)(x 6) right?
so 2 and 3
ok
now since we know we a negative 5.. we know that 6 has to be negative. so (x+1)(x-6)
so (x+1)(x-6)
solve those as separate equations .. x-6=0 and x+1=0
x=6 x=-1
yep. now.. the most important.. you need to plus these numbers back into the equation.. to check if both answers work.
ok
\[\sqrt{-1+10} =-1 - 2\]
\[\sqrt{6+10} = 6-2\]
sqrt9=-3 sqrt16 = 4
so x = 6 is your only answer? does that make sense?
\[\sqrt{9} =3 \neq -1-2 = -3\] \[\sqrt{16}=4 = 6-2=4\]

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