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boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{x+10}=x2\]
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
you first need to get rid of the radical.
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so square both sides.
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so you should have x+10 = x^24x4 ?
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
now move your terms all to one side and set it equal to 0 and factor or use the quadratic to solve for x
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
actualy... i typoed.. it should be \[x+10=x^{2}4x+4\]
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
ok i was confused trying to work that out
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
and the only reason i move to the right is cause I dont want to multiply by a negative 1.
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[x ^{2}5x6=0\]
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
you know how to factor or do the quadratic?
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
i have my text book here, these confuse me so much
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
ok. i would factor this. so you set up parens.. ( )( ) right? fill them with (x )(x ). now we are looking for 2 numbers that multiply to 6 and add to 5
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so 2 and 3 seem to work nice.. but they are not gonna get us to where we want because of the negative 5. so we try 1 and 6. (x 1)(x 6) right?
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
so 2 and 3
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
now since we know we a negative 5.. we know that 6 has to be negative. so (x+1)(x6)
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
so (x+1)(x6)
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
solve those as separate equations .. x6=0 and x+1=0
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
x=6 x=1
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
yep. now.. the most important.. you need to plus these numbers back into the equation.. to check if both answers work.
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{1+10} =1  2\]
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{6+10} = 62\]
 one year ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
sqrt9=3 sqrt16 = 4
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so x = 6 is your only answer? does that make sense?
 one year ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{9} =3 \neq 12 = 3\] \[\sqrt{16}=4 = 62=4\]
 one year ago
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