anonymous
  • anonymous
sqrt x+10 = x-2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt{x+10}=x-2\]
anonymous
  • anonymous
you first need to get rid of the radical.
anonymous
  • anonymous
so square both sides.

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anonymous
  • anonymous
ok
anonymous
  • anonymous
so you should have x+10 = x^2-4x-4 ?
anonymous
  • anonymous
now move your terms all to one side and set it equal to 0 and factor or use the quadratic to solve for x
anonymous
  • anonymous
ok
anonymous
  • anonymous
actualy... i typoed.. it should be \[x+10=x^{2}-4x+4\]
anonymous
  • anonymous
ok i was confused trying to work that out
anonymous
  • anonymous
and the only reason i move to the right is cause I dont want to multiply by a negative 1.
anonymous
  • anonymous
\[x ^{2}-5x-6=0\]
anonymous
  • anonymous
you know how to factor or do the quadratic?
anonymous
  • anonymous
i have my text book here, these confuse me so much
anonymous
  • anonymous
ok. i would factor this. so you set up parens.. ( )( ) right? fill them with (x )(x ). now we are looking for 2 numbers that multiply to 6 and add to -5
anonymous
  • anonymous
so 2 and 3 seem to work nice.. but they are not gonna get us to where we want because of the negative 5. so we try 1 and 6. (x 1)(x 6) right?
anonymous
  • anonymous
so 2 and 3
anonymous
  • anonymous
ok
anonymous
  • anonymous
now since we know we a negative 5.. we know that 6 has to be negative. so (x+1)(x-6)
anonymous
  • anonymous
so (x+1)(x-6)
anonymous
  • anonymous
solve those as separate equations .. x-6=0 and x+1=0
anonymous
  • anonymous
x=6 x=-1
anonymous
  • anonymous
yep. now.. the most important.. you need to plus these numbers back into the equation.. to check if both answers work.
anonymous
  • anonymous
ok
anonymous
  • anonymous
\[\sqrt{-1+10} =-1 - 2\]
anonymous
  • anonymous
\[\sqrt{6+10} = 6-2\]
anonymous
  • anonymous
sqrt9=-3 sqrt16 = 4
anonymous
  • anonymous
so x = 6 is your only answer? does that make sense?
anonymous
  • anonymous
\[\sqrt{9} =3 \neq -1-2 = -3\] \[\sqrt{16}=4 = 6-2=4\]

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