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boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{x+10}=x2\]
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
you first need to get rid of the radical.
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so square both sides.
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so you should have x+10 = x^24x4 ?
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
now move your terms all to one side and set it equal to 0 and factor or use the quadratic to solve for x
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
actualy... i typoed.. it should be \[x+10=x^{2}4x+4\]
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
ok i was confused trying to work that out
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
and the only reason i move to the right is cause I dont want to multiply by a negative 1.
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[x ^{2}5x6=0\]
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
you know how to factor or do the quadratic?
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
i have my text book here, these confuse me so much
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
ok. i would factor this. so you set up parens.. ( )( ) right? fill them with (x )(x ). now we are looking for 2 numbers that multiply to 6 and add to 5
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so 2 and 3 seem to work nice.. but they are not gonna get us to where we want because of the negative 5. so we try 1 and 6. (x 1)(x 6) right?
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
so 2 and 3
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
now since we know we a negative 5.. we know that 6 has to be negative. so (x+1)(x6)
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
so (x+1)(x6)
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
solve those as separate equations .. x6=0 and x+1=0
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
x=6 x=1
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
yep. now.. the most important.. you need to plus these numbers back into the equation.. to check if both answers work.
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{1+10} =1  2\]
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{6+10} = 62\]
 2 years ago

boomerang285 Group TitleBest ResponseYou've already chosen the best response.1
sqrt9=3 sqrt16 = 4
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
so x = 6 is your only answer? does that make sense?
 2 years ago

Nameless Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{9} =3 \neq 12 = 3\] \[\sqrt{16}=4 = 62=4\]
 2 years ago
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