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anonymous
 3 years ago
Ppl of the world.. here comes the Next question ..
anonymous
 3 years ago
Ppl of the world.. here comes the Next question ..

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its about the definition of the derivative >>>

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0were all beaming with anticipation...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Apply the definition of the d derivative to compute \[f \prime (x) \] where \[f(x)=3x ^{2}+x2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know .. \[f'(x)= 6x +1\] .. but my teacher said do it with details like long way to get this answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0.. i don't know how

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2i see well dw:1349804778192:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0XD ur handwritting is Funnie XP

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2lim delta x tends to 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0O_O sorry didn't mean to .. oops im sorry >> >_< sowwie

amorfide
 3 years ago
Best ResponseYou've already chosen the best response.1you have a function of x F(X)=3x²+x−2 to differentiate you multiply the coefficient of the unknown by the power of the unknown and decrease the power of the unknown by 1 for example f(x)=x² f'(x)=2(1)x^21=2x so f(x)=x f'(x)=1(1)x^11=x^0=1 if you have f(x)=2x² f'(x)=2(2)x^21=4x does this help? dw:1349804820461:dw

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2np @Alice_Dump did u get that ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0.. ppl brb .. gemme 5 minutes i need to do something .

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\[f'(x)=2\times 3x^{21} +1\times x^{11}0\times2x^{01}=6x +1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=3x^2+x2\] \[f(x+h)=3(x+h)^2+(x+h)2=3(x^2+2xh+h^2)+x+h2\] \[=3x^2+6xh+3h^2+x+h2\] \[f(x+h)f(x)=3x^2+6xh+3h^2+x+h2(32x^2+x2)\] \[=6xh+h+3h^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02 being constant will disappear

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0divide by \(h\) and get \[\frac{f(x+h)f(x)}{h}=6x+1+3h\] take the limit as \(h\to 0\) get \(6x+1\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you needed it done by hand right? not power rule it is a bunch of algebra, that is all only last step is calc, and that is taking the limit by replacing \(h\) by \(0\)

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.2indeed @satellite73 has illustrated the given problem nicely with the formula i have given you ...i think that clears evrything

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0question said "Apply the definition of the derivative to compute"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got the question now :] thnx ppl ^_^'
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