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Alice_Dump
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Ppl of the world.. here comes the Next question ..
 one year ago
 one year ago
Alice_Dump Group Title
Ppl of the world.. here comes the Next question ..
 one year ago
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This Question is Closed

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
its about the definition of the derivative >>>
 one year ago

SmithsAccount Group TitleBest ResponseYou've already chosen the best response.0
were all beaming with anticipation...
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
Apply the definition of the d derivative to compute \[f \prime (x) \] where \[f(x)=3x ^{2}+x2\]
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
i know .. \[f'(x)= 6x +1\] .. but my teacher said do it with details like long way to get this answer
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
.. i don't know how
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
i see well dw:1349804778192:dw
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
XD ur handwritting is Funnie XP
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
lim delta x tends to 0
 one year ago

SmithsAccount Group TitleBest ResponseYou've already chosen the best response.0
ikr!
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
O_O sorry didn't mean to .. oops im sorry >> >_< sowwie
 one year ago

amorfide Group TitleBest ResponseYou've already chosen the best response.1
you have a function of x F(X)=3x²+x−2 to differentiate you multiply the coefficient of the unknown by the power of the unknown and decrease the power of the unknown by 1 for example f(x)=x² f'(x)=2(1)x^21=2x so f(x)=x f'(x)=1(1)x^11=x^0=1 if you have f(x)=2x² f'(x)=2(2)x^21=4x does this help? dw:1349804820461:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
np @Alice_Dump did u get that ?
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
.. ppl brb .. gemme 5 minutes i need to do something .
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
wait okie >_<
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[f'(x)=2\times 3x^{21} +1\times x^{11}0\times2x^{01}=6x +1\]
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.0
2*3x^(21)+x(11)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.4
\[f(x)=3x^2+x2\] \[f(x+h)=3(x+h)^2+(x+h)2=3(x^2+2xh+h^2)+x+h2\] \[=3x^2+6xh+3h^2+x+h2\] \[f(x+h)f(x)=3x^2+6xh+3h^2+x+h2(32x^2+x2)\] \[=6xh+h+3h^2\]
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.0
2 being constant will disappear
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.4
divide by \(h\) and get \[\frac{f(x+h)f(x)}{h}=6x+1+3h\] take the limit as \(h\to 0\) get \(6x+1\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.4
you needed it done by hand right? not power rule it is a bunch of algebra, that is all only last step is calc, and that is taking the limit by replacing \(h\) by \(0\)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
indeed @satellite73 has illustrated the given problem nicely with the formula i have given you ...i think that clears evrything
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.4
question said "Apply the definition of the derivative to compute"
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.4
@AravindG thanks
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
:} back ..
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
i got the question now :] thnx ppl ^_^'
 one year ago

Alice_Dump Group TitleBest ResponseYou've already chosen the best response.0
heehehe
 one year ago
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