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its about the definition of the derivative >>>

were all beaming with anticipation...

Apply the definition of the d derivative to compute \[f \prime (x) \] where \[f(x)=3x ^{2}+x-2\]

6x+1

6x+1

-..- i don't know how

i see well
|dw:1349804778192:dw|

XD ur hand-writting is Funnie XP

lim delta x tends to 0

ikr!

O_O sorry didn't mean to .. oops im sorry >> >_< sowwie

np @Alice_Dump did u get that ?

-..- ppl brb .. gemme 5 minutes i need to do something .

wait okie >_<

\[f'(x)=2\times 3x^{2-1} +1\times x^{1-1}-0\times2x^{0-1}=6x +1\]

2*3x^(2-1)+x(1-1)

2 being constant will disappear

divide by \(h\) and get
\[\frac{f(x+h)-f(x)}{h}=6x+1+3h\] take the limit as \(h\to 0\) get \(6x+1\)

question said "Apply the definition of the derivative to compute"

yw :)

:} back ..

i got the question now :] thnx ppl ^_^'

heehehe