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Kris5
help! 4 divided by 4 + radical 7 and 3 divided by radical 5 - 2
\[\frac{ 4 }{ 4 + \sqrt{7} }\]
\[\frac{ 4 }{ 4 + \sqrt{7} } (\frac{ 4 - \sqrt{7} }{ 4 - \sqrt{7} })\]
\[\frac{ 4(4-\sqrt{7}) }{ 4^{2} + 4\sqrt{7} - 4\sqrt{7} - \sqrt{7}^{2} }\]
\[\frac{ 16 - 4\sqrt{7} }{ 16 - 7 } = \frac{ 16 - 4\sqrt{7} }{ 9 }\]