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Kris5

  • 3 years ago

help! 4 divided by 4 + radical 7 and 3 divided by radical 5 - 2

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  1. JakeV8
    • 3 years ago
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    \[\frac{ 4 }{ 4 + \sqrt{7} }\]

  2. JakeV8
    • 3 years ago
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    \[\frac{ 4 }{ 4 + \sqrt{7} } (\frac{ 4 - \sqrt{7} }{ 4 - \sqrt{7} })\]

  3. JakeV8
    • 3 years ago
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    \[\frac{ 4(4-\sqrt{7}) }{ 4^{2} + 4\sqrt{7} - 4\sqrt{7} - \sqrt{7}^{2} }\]

  4. JakeV8
    • 3 years ago
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    \[\frac{ 16 - 4\sqrt{7} }{ 16 - 7 } = \frac{ 16 - 4\sqrt{7} }{ 9 }\]

  5. Kris5
    • 3 years ago
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    thanks!

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