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pls help

b was the confusing one,so am to integrate t-cosx 2twice?

Yes, because you are derivating twice, but then you get 2 arbitrary constants.

whats this for dy(0)/dx=2
what do i need it for?

my first integration i got tx-sin(x)+c

so how do i use this dy(0)/dx=2?

tx-sin(x)+c=dy/dx
so
t*0-sin(0)+c=2
Do you understand that?

yeah

so what about the y(0)=-2?

So, did you got the answer?

i will integrate this tx-sin(x)+c again?

yes

because it is equal to dy/dx, and you want y

i got (tx^2/2)+cos(x)+c

you forgot to sonsider the constant of the previous integration

There will be two constants in this case, because its the second derivative.

cx+tx^2/2+cos(x)+c?

the 1st one is 2 right?

yes

ok thanks alot for your help :)

You are welcome