Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

i need help with number 3 a and b

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

1 Attachment
pls help
The opposite of derivative is integration, so in a you need to integrate once and on b, twice. Since the indefinite integral (with no limits of integration) gives you an arbitrary constant that disapears when you derivate, you need a way to find that constant because any number would satisfy the derivative formula since it would disapear when you derivated, thats why they give you one value of the function you want to find. Is it too confusing the way I explained or you got it?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

b was the confusing one,so am to integrate t-cosx 2twice?
Yes, because you are derivating twice, but then you get 2 arbitrary constants.
whats this for dy(0)/dx=2 what do i need it for?
my first integration i got tx-sin(x)+c
Your integration is fine and now you need to determine c, thats when you use dy(0)/dx=2, because by integrating once, you got dy/dx
so how do i use this dy(0)/dx=2?
tx-sin(x)+c=dy/dx so t*0-sin(0)+c=2 Do you understand that?
so what about the y(0)=-2?
you have dy/dx, but you want y, so you integrate again, and youll need this to find the other constant.
So, did you got the answer?
i will integrate this tx-sin(x)+c again?
because it is equal to dy/dx, and you want y
i got (tx^2/2)+cos(x)+c
you forgot to sonsider the constant of the previous integration
There will be two constants in this case, because its the second derivative.
Yep thats it, but keep in mind that the c's are different, and the first one you should already have it as a number
the 1st one is 2 right?
ok thanks alot for your help :)
You are welcome

Not the answer you are looking for?

Search for more explanations.

Ask your own question