anonymous
  • anonymous
i need help with number 3 a and b
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
pls help
anonymous
  • anonymous
The opposite of derivative is integration, so in a you need to integrate once and on b, twice. Since the indefinite integral (with no limits of integration) gives you an arbitrary constant that disapears when you derivate, you need a way to find that constant because any number would satisfy the derivative formula since it would disapear when you derivated, thats why they give you one value of the function you want to find. Is it too confusing the way I explained or you got it?

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anonymous
  • anonymous
b was the confusing one,so am to integrate t-cosx 2twice?
anonymous
  • anonymous
Yes, because you are derivating twice, but then you get 2 arbitrary constants.
anonymous
  • anonymous
whats this for dy(0)/dx=2 what do i need it for?
anonymous
  • anonymous
my first integration i got tx-sin(x)+c
anonymous
  • anonymous
Your integration is fine and now you need to determine c, thats when you use dy(0)/dx=2, because by integrating once, you got dy/dx
anonymous
  • anonymous
so how do i use this dy(0)/dx=2?
anonymous
  • anonymous
tx-sin(x)+c=dy/dx so t*0-sin(0)+c=2 Do you understand that?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
so what about the y(0)=-2?
anonymous
  • anonymous
you have dy/dx, but you want y, so you integrate again, and youll need this to find the other constant.
anonymous
  • anonymous
So, did you got the answer?
anonymous
  • anonymous
i will integrate this tx-sin(x)+c again?
anonymous
  • anonymous
yes
anonymous
  • anonymous
because it is equal to dy/dx, and you want y
anonymous
  • anonymous
i got (tx^2/2)+cos(x)+c
anonymous
  • anonymous
you forgot to sonsider the constant of the previous integration
anonymous
  • anonymous
There will be two constants in this case, because its the second derivative.
anonymous
  • anonymous
cx+tx^2/2+cos(x)+c?
anonymous
  • anonymous
Yep thats it, but keep in mind that the c's are different, and the first one you should already have it as a number
anonymous
  • anonymous
the 1st one is 2 right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok thanks alot for your help :)
anonymous
  • anonymous
You are welcome

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