abz_tech
solve:
2^(2x+1)  33(2^x) +16 = 0



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asnaseer
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let \(y=2^x\) and substitute into your equation. you should end up with a quadratic in y. solve that, then find x.

abz_tech
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0_o

asnaseer
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remember that \(2^{2x+1}=2\times2^{2x}=2\times(2^x)^2\)

abz_tech
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ah!

asnaseer
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:)

abz_tech
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thank you so much

asnaseer
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yw :)

abz_tech
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maths is amazing 0_o

asnaseer
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it's good when you get those "aha!" moments! :D

abz_tech
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:)