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petewe Group TitleBest ResponseYou've already chosen the best response.0
with matrices
 2 years ago

richardlong369 Group TitleBest ResponseYou've already chosen the best response.0
well
 2 years ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
2y = 4x + 2 2y = x + 7 Thus, 4x + 2 = x + 7 4x + x = 7  2 5x = 5 x = 1 Put x = 1 into any of the two equations 2y = 4(1) + 2 2y = 4 + 2 2y = 6 y = 3 Therefore (x, y) = (1, 3)
 2 years ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
WITH matrices.
 2 years ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\left[\begin{matrix}4 & 2 \\ 1 & 2\end{matrix}\right]\left(\begin{matrix}x \\ y\end{matrix}\right) = \left(\begin{matrix}2 \\ 7\end{matrix}\right)\] \[\left(\begin{matrix}x \\ y\end{matrix}\right) = \left[\begin{matrix}4 & 2 \\ 1 & 2\end{matrix}\right]^{1} \left(\begin{matrix}2 \\ 7\end{matrix}\right)\]
 2 years ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 4(2) 2(1) }\left[\begin{matrix}2 & 2 \\ 1 & 4\end{matrix}\right]\left(\begin{matrix}2 \\ 7\end{matrix}\right)\]
 2 years ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 10}\left[\begin{matrix}2 & 2 \\ 1 & 4\end{matrix}\right]\left(\begin{matrix}2 \\ 7\end{matrix}\right)\]\]
 2 years ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\[\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 10}]\left(\begin{matrix}4  14 \\ 2  28\end{matrix}\right)\]\]\]
 2 years ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 10}]\left(\begin{matrix} 10 \\ 30\end{matrix}\right) = \left(\begin{matrix}1 \\ 3\end{matrix}\right)\]
 2 years ago
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