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petewe Group TitleBest ResponseYou've already chosen the best response.0
with matrices
 one year ago

richardlong369 Group TitleBest ResponseYou've already chosen the best response.0
well
 one year ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
2y = 4x + 2 2y = x + 7 Thus, 4x + 2 = x + 7 4x + x = 7  2 5x = 5 x = 1 Put x = 1 into any of the two equations 2y = 4(1) + 2 2y = 4 + 2 2y = 6 y = 3 Therefore (x, y) = (1, 3)
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
WITH matrices.
 one year ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\left[\begin{matrix}4 & 2 \\ 1 & 2\end{matrix}\right]\left(\begin{matrix}x \\ y\end{matrix}\right) = \left(\begin{matrix}2 \\ 7\end{matrix}\right)\] \[\left(\begin{matrix}x \\ y\end{matrix}\right) = \left[\begin{matrix}4 & 2 \\ 1 & 2\end{matrix}\right]^{1} \left(\begin{matrix}2 \\ 7\end{matrix}\right)\]
 one year ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 4(2) 2(1) }\left[\begin{matrix}2 & 2 \\ 1 & 4\end{matrix}\right]\left(\begin{matrix}2 \\ 7\end{matrix}\right)\]
 one year ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 10}\left[\begin{matrix}2 & 2 \\ 1 & 4\end{matrix}\right]\left(\begin{matrix}2 \\ 7\end{matrix}\right)\]\]
 one year ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\[\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 10}]\left(\begin{matrix}4  14 \\ 2  28\end{matrix}\right)\]\]\]
 one year ago

KKJ Group TitleBest ResponseYou've already chosen the best response.1
\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ 1 }{ 10}]\left(\begin{matrix} 10 \\ 30\end{matrix}\right) = \left(\begin{matrix}1 \\ 3\end{matrix}\right)\]
 one year ago
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