A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
3/8X+3/8=3/8X+1/8
anonymous
 3 years ago
3/8X+3/8=3/8X+1/8

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0make the LCM 8x on both sides,so that they can cancel, then the equation becomes; 3+3x=3+x now u can get x=3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0math2! you'd better use some parentheses to clarify! Which one do you mean? 1. \[\frac{ 3 }{ 8x }+\frac{ 3 }{ 8 }=\frac{ 3 }{ 8x }+\frac{ 1 }{ 8 }\] 2. \[\frac{ 3 }{ 8 }x+\frac{ 3 }{ 8 }=\frac{ 3 }{ 8 }x+\frac{ 1 }{ 8 }\] It could go on either ways. But most likely, what you mean is the second one. If so, you must do as follows: 1. Multiply all terms by 8 in order to cancel all 8's in denominators. Then it will be like this: \[3x+3=3x+1\] Then \[3x+3x=13\rightarrow 6x=2\rightarrow x=\frac{ 1 }{ 3 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0MathPhysics i think you just changed the question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0pasta! Why are you saying this?!! Quite the contrary, I think this is you who did so!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I THINK THE "X" IS PART OF THE DENOMINATOR NOT THE NUMERATOR

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Might be! If you read my post carefully, you'd notice that I already mentioned it. He hasn't determined what he exactly meant. Anyways, If he meant the first possibility I mentioned, you'd be right then.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.