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math2
 3 years ago
3/8X+3/8=3/8X+1/8
math2
 3 years ago
3/8X+3/8=3/8X+1/8

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pasta
 3 years ago
Best ResponseYou've already chosen the best response.0make the LCM 8x on both sides,so that they can cancel, then the equation becomes; 3+3x=3+x now u can get x=3

MathPhysics
 3 years ago
Best ResponseYou've already chosen the best response.1math2! you'd better use some parentheses to clarify! Which one do you mean? 1. \[\frac{ 3 }{ 8x }+\frac{ 3 }{ 8 }=\frac{ 3 }{ 8x }+\frac{ 1 }{ 8 }\] 2. \[\frac{ 3 }{ 8 }x+\frac{ 3 }{ 8 }=\frac{ 3 }{ 8 }x+\frac{ 1 }{ 8 }\] It could go on either ways. But most likely, what you mean is the second one. If so, you must do as follows: 1. Multiply all terms by 8 in order to cancel all 8's in denominators. Then it will be like this: \[3x+3=3x+1\] Then \[3x+3x=13\rightarrow 6x=2\rightarrow x=\frac{ 1 }{ 3 }\]

pasta
 3 years ago
Best ResponseYou've already chosen the best response.0MathPhysics i think you just changed the question

MathPhysics
 3 years ago
Best ResponseYou've already chosen the best response.1pasta! Why are you saying this?!! Quite the contrary, I think this is you who did so!!

pasta
 3 years ago
Best ResponseYou've already chosen the best response.0I THINK THE "X" IS PART OF THE DENOMINATOR NOT THE NUMERATOR

MathPhysics
 3 years ago
Best ResponseYou've already chosen the best response.1Might be! If you read my post carefully, you'd notice that I already mentioned it. He hasn't determined what he exactly meant. Anyways, If he meant the first possibility I mentioned, you'd be right then.
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