Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
nickymarden
Group Title
Given the function... is it derivable at the point P(0,1) ?
 2 years ago
 2 years ago
nickymarden Group Title
Given the function... is it derivable at the point P(0,1) ?
 2 years ago
 2 years ago

This Question is Closed

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
use the definition: the function is derivable at x=0 if \[ \large \lim_{x\to0}\frac{f(x)f(0)}{x0}=\lim_{x\to0}\frac{f(x)+1}{x} \]
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
this limit has to exist. so u now turn to onesided limits.
 2 years ago

nickymarden Group TitleBest ResponseYou've already chosen the best response.0
Oh yeeah, thank you so much. After you use the rules you forget the definition.
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
u r welcome
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
actually it is easier than that, although of course @helder_edwin is correct
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
just take the derivative of each piece, and replace \(x\) by \(0\) if you get the same answer, then yes, if you get a different answer, then no
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you can pretty much do it with your eyeballs first one is 3 second one is \(10x+3\)and when you replace \(x\) by 0 in both you get 3
 2 years ago

nickymarden Group TitleBest ResponseYou've already chosen the best response.0
haha thanks :) Not everyone can do it with their eyeballs ;)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.