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by the way...the words don't have to be legitimate words

goat
boat

sale

not real words....

it's just how many possible 4 letter words

rearrangement

|dw:1349841083602:dw| infinity

The solution is a finite number.

not infinite...

214,358,881

??

that's big

\[\pi\]

....careful....

There are 11 places, but only 8 different letters

exactly! I was thinking of that, however, they don't have to be words!

i'd say over 9000

It is either 11^8 or 8^11.

where are you getting those numbers....

Ahhh....yes...

however I know im wrong...lets go back, ohgod....4 letter words :0

Oops.... forgot to add the 4-letter word variable

it's much more difficult than what you think.....

I suppose LLLG is a valid "word"... *hint hint*

11^8 still doesn't make sense though

this changes it to 11^11*4, or 11^11^4?!?! and yes, I know why because it can be any word

Well 11 doesn't matter anymore...

Here is the answer\[11!(1-\frac{ 1 }{ 6! })\]

no...

i don't even ahve any idea how you got that

hum....11 does matter because thats the number of letters we have....

was I close?

oh! 11^4?

4^11

i doubt there's even "11" in the solution

Do you even have the answer?

and no i do not...im trying to learn it too

i believe the answer should be less than 1960

can you explain to be what 11P4/3 is in the other question? im bad at reading..math..

ironic that you're asking someone with a picture that says "i hate math"

where's 11P4/3?

almost down a page...

what were you trying todo, or explain in the later sentences of your text?

same thing i was trying in teh beginning

hum...

11.10.9....(so on)
--------------
4

no, * 4

that's not the solution here though...like i pointed out in the other question

11,10....
-------------
2^4..... This ones it

no idea where you got that...

http://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.17407.html

I might continue tommorow, I am interested..

goofnight and thank you!

i told you it's very difficult...