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richyw Group Title

Having trouble with some algebra

  • one year ago
  • one year ago

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  1. lgbasallote Group Title
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    welcome to the club

    • one year ago
  2. richyw Group Title
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    my solutions manual goes from \[\vec{E}=k_eq\left( \frac{1}{(x-a)^2}-\frac{1}{(x+a)^2}\right)\hat{i}\]to\[\vec{E}=k_eq\frac{4ax}{(x^2-a^2)^2}\hat{i}\] and I can't quite remember how to get that!

    • one year ago
  3. richyw Group Title
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    I can get to \[\vec{E}=k_eq\left(\frac{4ax}{(x-a)^2(x+a)^2}\right)\hat{i}\] so basically I have forgotten how to deal with the denominator :O

    • one year ago
  4. richyw Group Title
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    without expanding it all out of course...

    • one year ago
  5. ganeshie8 Group Title
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    \(\vec{E}=k_eq\left(\frac{4ax}{(x-a)^2(x+a)^2}\right)\hat{i} \) \(\vec{E}=k_eq\left(\frac{4ax}{((x-a)(x+a))^2}\right)\hat{i} \)

    • one year ago
  6. richyw Group Title
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    oh wow

    • one year ago
  7. richyw Group Title
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    i need to sleep haha

    • one year ago
  8. ganeshie8 Group Title
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    haha i agree ;p

    • one year ago
  9. richyw Group Title
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    thanks a lot

    • one year ago
  10. ganeshie8 Group Title
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    np :)

    • one year ago
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