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richyw
 3 years ago
Having trouble with some algebra
richyw
 3 years ago
Having trouble with some algebra

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lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0welcome to the club

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1my solutions manual goes from \[\vec{E}=k_eq\left( \frac{1}{(xa)^2}\frac{1}{(x+a)^2}\right)\hat{i}\]to\[\vec{E}=k_eq\frac{4ax}{(x^2a^2)^2}\hat{i}\] and I can't quite remember how to get that!

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1I can get to \[\vec{E}=k_eq\left(\frac{4ax}{(xa)^2(x+a)^2}\right)\hat{i}\] so basically I have forgotten how to deal with the denominator :O

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1without expanding it all out of course...

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\vec{E}=k_eq\left(\frac{4ax}{(xa)^2(x+a)^2}\right)\hat{i} \) \(\vec{E}=k_eq\left(\frac{4ax}{((xa)(x+a))^2}\right)\hat{i} \)
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