Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
welcome to the club
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
my solutions manual goes from \[\vec{E}=k_eq\left( \frac{1}{(xa)^2}\frac{1}{(x+a)^2}\right)\hat{i}\]to\[\vec{E}=k_eq\frac{4ax}{(x^2a^2)^2}\hat{i}\] and I can't quite remember how to get that!
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
I can get to \[\vec{E}=k_eq\left(\frac{4ax}{(xa)^2(x+a)^2}\right)\hat{i}\] so basically I have forgotten how to deal with the denominator :O
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
without expanding it all out of course...
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(\vec{E}=k_eq\left(\frac{4ax}{(xa)^2(x+a)^2}\right)\hat{i} \) \(\vec{E}=k_eq\left(\frac{4ax}{((xa)(x+a))^2}\right)\hat{i} \)
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
i need to sleep haha
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
haha i agree ;p
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
thanks a lot
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.