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Having trouble with some algebra

Mathematics
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welcome to the club
my solutions manual goes from \[\vec{E}=k_eq\left( \frac{1}{(x-a)^2}-\frac{1}{(x+a)^2}\right)\hat{i}\]to\[\vec{E}=k_eq\frac{4ax}{(x^2-a^2)^2}\hat{i}\] and I can't quite remember how to get that!
I can get to \[\vec{E}=k_eq\left(\frac{4ax}{(x-a)^2(x+a)^2}\right)\hat{i}\] so basically I have forgotten how to deal with the denominator :O

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Other answers:

without expanding it all out of course...
\(\vec{E}=k_eq\left(\frac{4ax}{(x-a)^2(x+a)^2}\right)\hat{i} \) \(\vec{E}=k_eq\left(\frac{4ax}{((x-a)(x+a))^2}\right)\hat{i} \)
oh wow
i need to sleep haha
haha i agree ;p
thanks a lot
np :)

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