A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0welcome to the club

richyw
 2 years ago
Best ResponseYou've already chosen the best response.1my solutions manual goes from \[\vec{E}=k_eq\left( \frac{1}{(xa)^2}\frac{1}{(x+a)^2}\right)\hat{i}\]to\[\vec{E}=k_eq\frac{4ax}{(x^2a^2)^2}\hat{i}\] and I can't quite remember how to get that!

richyw
 2 years ago
Best ResponseYou've already chosen the best response.1I can get to \[\vec{E}=k_eq\left(\frac{4ax}{(xa)^2(x+a)^2}\right)\hat{i}\] so basically I have forgotten how to deal with the denominator :O

richyw
 2 years ago
Best ResponseYou've already chosen the best response.1without expanding it all out of course...

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.1\(\vec{E}=k_eq\left(\frac{4ax}{(xa)^2(x+a)^2}\right)\hat{i} \) \(\vec{E}=k_eq\left(\frac{4ax}{((xa)(x+a))^2}\right)\hat{i} \)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.