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yes now how do i get the height into this can u show the working

speed will be the resultant of v cos alpha and wt u found out?

Yeah speed will be
\[\sqrt {( v\ \cos \alpha)^2+x^2}\]

\[x^2-(u\sin \alpha)^2=2\times (-g)\times h\]

|dw:1349871122014:dw|

Actually the velocity has two components
v cos alpha and x
Speed will be the magnitude

yes

thanks :)

welcome (:

thanks algebraic :)