Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
ksaimouli
Group Title
 2 years ago
 2 years ago
ksaimouli Group Title
 2 years ago
 2 years ago

This Question is Closed

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
In the diagram above, a 1.0–kg cart and a 2.0–kg cart are connected by a rope. The spring scale reads 10 N. What is the tension in the rope connecting the two carts? Neglect any friction. 30 N 10 N 6.7 N 5.0 N 3.3 N
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
As a guess, 10N is being applied on the 3kg system intuition says 10/3 N is being exerted on the 1kg object to achieve the acceleration, so the tension is 10/3N. Probably incorrect as I didn't include the 2kg mass.
 2 years ago

ujjwal Group TitleBest ResponseYou've already chosen the best response.1
Divide total force into 3 parts (which will give you 3 parts of 3.3 N).. 2 parts pull 2 kg and 1 part pull 1 kg.. 2 parts of 3.3N (total 6.6N) pulls 2 kg.. So, beyond it force applied (on 1 kg via rope)= remaining force=3.3 N which will be the tension in rope.. So, tension= 3.3 N
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
Another way of looking at itdw:1349896310366:dwdw:1349896342952:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i did not get u uujawal
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
ok but y did u divid 10/3
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
To work out acceleration, treat the whole system as a mass m=3kg. F=10N Obviously, a=10/3 (m/s^2) So, the small string's got to pull the small mass enough to make it accelerate at 10/3 (m/s^2). What force can do that? F=ma=1*(10/3) 10/3N
 2 years ago

ujjwal Group TitleBest ResponseYou've already chosen the best response.1
@henpen 's approach is better and more formal.. What i said was more informal and you couldn't write it that way in your exam! Follow henpen's process @ksaimouli
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
alright thx both of u
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.