Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

  • This Question is Closed
  1. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    In the diagram above, a 1.0–kg cart and a 2.0–kg cart are connected by a rope. The spring scale reads 10 N. What is the tension in the rope connecting the two carts? Neglect any friction. 30 N 10 N 6.7 N 5.0 N 3.3 N

    • one year ago
  2. henpen Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    As a guess, 10N is being applied on the 3kg system- intuition says 10/3 N is being exerted on the 1kg object to achieve the acceleration, so the tension is 10/3N. Probably incorrect as I didn't include the 2kg mass.

    • one year ago
  3. ujjwal Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Divide total force into 3 parts (which will give you 3 parts of 3.3 N).. 2 parts pull 2 kg and 1 part pull 1 kg.. 2 parts of 3.3N (total 6.6N) pulls 2 kg.. So, beyond it force applied (on 1 kg via rope)= remaining force=3.3 N which will be the tension in rope.. So, tension= 3.3 N

    • one year ago
  4. henpen Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Another way of looking at it|dw:1349896310366:dw||dw:1349896342952:dw|

    • one year ago
  5. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i did not get u uujawal

    • one year ago
  6. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok but y did u divid 10/3

    • one year ago
  7. henpen Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    To work out acceleration, treat the whole system as a mass m=3kg. F=10N Obviously, a=10/3 (m/s^2) So, the small string's got to pull the small mass enough to make it accelerate at 10/3 (m/s^2). What force can do that? F=ma=1*(10/3) 10/3N

    • one year ago
  8. ujjwal Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @henpen 's approach is better and more formal.. What i said was more informal and you couldn't write it that way in your exam! Follow henpen's process @ksaimouli

    • one year ago
  9. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    alright thx both of u

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.