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UMULAS
Group Title
What is the solution to the equation log 2 x – log 2 3 = 2 ?
 2 years ago
 2 years ago
UMULAS Group Title
What is the solution to the equation log 2 x – log 2 3 = 2 ?
 2 years ago
 2 years ago

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psi9epsilon Group TitleBest ResponseYou've already chosen the best response.0
is it log 2x or is it log x to the base 2, and also log 23 or log 3 to base 2
 2 years ago

psi9epsilon Group TitleBest ResponseYou've already chosen the best response.0
please retype the question
 2 years ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \log_2 x  \log_2 3 = 2\]this i guess
 2 years ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
yes the one the np did
 2 years ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
I mean as usual logs i didd x  = 2 3 But the answer is not 6.
 2 years ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \log_2 x = 2+ \log_2 3\]\[\huge 2^{\log_2 x} = 2^{2 + \log_2 3}\]\[\huge x = 2^2 \times 2 ^{\log_2 3}\]\[x = 4 \times 3\]
 2 years ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
\_/ what how did you get he log and the 2 together?
 2 years ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
o.O which one, how to type it or how to do it?
 2 years ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
how to do it.
 2 years ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \log_2 x = 2 + \log_2 3\]then 2^(everything)\[\huge 2^{\log_2 x} = 2^{2+\log_2 3}\]\[\huge 2^{\log_2 x} = x\]and the other side using a^(m+n) = a^m * a^n \[\huge 2^{2+\log_2 3} = 2^2 \times 2 ^{\log_2 3} = 4 \times 3\]
 2 years ago
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