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UMULAS
Group Title
What is the solution to the equation log 2 x – log 2 3 = 2 ?
 one year ago
 one year ago
UMULAS Group Title
What is the solution to the equation log 2 x – log 2 3 = 2 ?
 one year ago
 one year ago

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psi9epsilon Group TitleBest ResponseYou've already chosen the best response.0
is it log 2x or is it log x to the base 2, and also log 23 or log 3 to base 2
 one year ago

psi9epsilon Group TitleBest ResponseYou've already chosen the best response.0
please retype the question
 one year ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \log_2 x  \log_2 3 = 2\]this i guess
 one year ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
yes the one the np did
 one year ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
I mean as usual logs i didd x  = 2 3 But the answer is not 6.
 one year ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \log_2 x = 2+ \log_2 3\]\[\huge 2^{\log_2 x} = 2^{2 + \log_2 3}\]\[\huge x = 2^2 \times 2 ^{\log_2 3}\]\[x = 4 \times 3\]
 one year ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
\_/ what how did you get he log and the 2 together?
 one year ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
o.O which one, how to type it or how to do it?
 one year ago

UMULAS Group TitleBest ResponseYou've already chosen the best response.0
how to do it.
 one year ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \log_2 x = 2 + \log_2 3\]then 2^(everything)\[\huge 2^{\log_2 x} = 2^{2+\log_2 3}\]\[\huge 2^{\log_2 x} = x\]and the other side using a^(m+n) = a^m * a^n \[\huge 2^{2+\log_2 3} = 2^2 \times 2 ^{\log_2 3} = 4 \times 3\]
 one year ago
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