A community for students.
Here's the question you clicked on:
 0 viewing
UMULAS
 3 years ago
What is the solution to the equation log 2 x – log 2 3 = 2 ?
UMULAS
 3 years ago
What is the solution to the equation log 2 x – log 2 3 = 2 ?

This Question is Closed

psi9epsilon
 3 years ago
Best ResponseYou've already chosen the best response.0is it log 2x or is it log x to the base 2, and also log 23 or log 3 to base 2

psi9epsilon
 3 years ago
Best ResponseYou've already chosen the best response.0please retype the question

nphuongsun93
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \log_2 x  \log_2 3 = 2\]this i guess

UMULAS
 3 years ago
Best ResponseYou've already chosen the best response.0I mean as usual logs i didd x  = 2 3 But the answer is not 6.

nphuongsun93
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \log_2 x = 2+ \log_2 3\]\[\huge 2^{\log_2 x} = 2^{2 + \log_2 3}\]\[\huge x = 2^2 \times 2 ^{\log_2 3}\]\[x = 4 \times 3\]

UMULAS
 3 years ago
Best ResponseYou've already chosen the best response.0\_/ what how did you get he log and the 2 together?

nphuongsun93
 3 years ago
Best ResponseYou've already chosen the best response.1o.O which one, how to type it or how to do it?

nphuongsun93
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \log_2 x = 2 + \log_2 3\]then 2^(everything)\[\huge 2^{\log_2 x} = 2^{2+\log_2 3}\]\[\huge 2^{\log_2 x} = x\]and the other side using a^(m+n) = a^m * a^n \[\huge 2^{2+\log_2 3} = 2^2 \times 2 ^{\log_2 3} = 4 \times 3\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.