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UMULAS

What is the solution to the equation log 2 x – log 2 3 = 2 ?

  • one year ago
  • one year ago

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  1. psi9epsilon
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    is it log 2x or is it log x to the base 2, and also log 23 or log 3 to base 2

    • one year ago
  2. psi9epsilon
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    please retype the question

    • one year ago
  3. nphuongsun93
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    \[\huge \log_2 x - \log_2 3 = 2\]this i guess

    • one year ago
  4. UMULAS
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    yes the one the np did

    • one year ago
  5. UMULAS
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    I mean as usual logs i didd x - = 2 3 But the answer is not 6.

    • one year ago
  6. nphuongsun93
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    \[\huge \log_2 x = 2+ \log_2 3\]\[\huge 2^{\log_2 x} = 2^{2 + \log_2 3}\]\[\huge x = 2^2 \times 2 ^{\log_2 3}\]\[x = 4 \times 3\]

    • one year ago
  7. UMULAS
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    \_/ what how did you get he log and the 2 together?

    • one year ago
  8. nphuongsun93
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    o.O which one, how to type it or how to do it?

    • one year ago
  9. UMULAS
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    how to do it.

    • one year ago
  10. nphuongsun93
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    \[\huge \log_2 x = 2 + \log_2 3\]then 2^(everything)\[\huge 2^{\log_2 x} = 2^{2+\log_2 3}\]\[\huge 2^{\log_2 x} = x\]and the other side using a^(m+n) = a^m * a^n \[\huge 2^{2+\log_2 3} = 2^2 \times 2 ^{\log_2 3} = 4 \times 3\]

    • one year ago
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