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jasmynarteaga

can someone help me with geometry crap?

  • one year ago
  • one year ago

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  1. yummydum
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    what's the question here?

    • one year ago
  2. yummydum
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    can you take a picture of your screen because its asking me to log into ur book...send a picture n ill help

    • one year ago
  3. jasmynarteaga
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    i cant. thats ok. thanks for ur help anyways! i fanned u anyways! :D

    • one year ago
  4. yummydum
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    just go to your screen and press Ctrl and PrtSc on your keyboard....then paste the picture on a document and attach it :)

    • one year ago
  5. jasmynarteaga
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    oh ok.

    • one year ago
  6. jasmynarteaga
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    # 15 please!

    • one year ago
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  7. jasmynarteaga
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    you might need to zoom in. sorry.

    • one year ago
  8. yummydum
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    we know that \( x+(x+y)=180\) and \((x+y)=2y\) ......look at the graph now just solve :) \[x+x+y=180\]\[2x+y=180\]\[x+y=90\]\[y=90-x\]then plug that into the second equation \(x+y=2y\)\[x+(90-x)=2(90-x)\]\[90=180-2x\]\[-90=-2x\]\[x=45\]now put that back into \(y=90-x\) \[y=90-45\]\[y=45\] we get \(x=45\) and \(y=45\) so im not sure if the picture is just not to scale but check the answer in the back of the book and let me know :)

    • one year ago
  9. yummydum
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    i meant to say to look at the picture not the graph, sorry

    • one year ago
  10. jasmynarteaga
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    thats ok. Thanks lots! it makes sense now :D

    • one year ago
  11. yummydum
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    is the answer correct though??

    • one year ago
  12. yummydum
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    did you check the answer??

    • one year ago
  13. jasmynarteaga
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    no i didnt. hold on.

    • one year ago
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