HELP PLEASE!!!: f(x)=3x-4 g(x)=-x^2 1.(f o g)(-2) 2.(f o f)(-2) f(x)=2x g(x)=x^2+2 h(x)=-4x+3 1.(h o f)o g

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HELP PLEASE!!!: f(x)=3x-4 g(x)=-x^2 1.(f o g)(-2) 2.(f o f)(-2) f(x)=2x g(x)=x^2+2 h(x)=-4x+3 1.(h o f)o g

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for the first part, what does the 2 do? i know how to solve (f o g)(x)
(f o f)(-2) is basically saying f( f(-2) ), in other words, in 3x-4, replace x with ( 3x - 4 ) so you get f o f(-2) = 3( 3(-2) - 4 ) - 4 then simplify.
Oh ok

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and how would i do the second part?
like h(f(x)(g(x))? but then how do i solve it
(h o f)(x) = h(f(x)) so (h o f)o g = h(f(x)) o g = h( f ( g(x) ) ) f(g(x)) = 2(x^2+2) so h ( f ( g ( x ) ) ) = -4(2(x^2+2) )+3 Is this clear enough?
yes thank you
Glad I helped.
wait but if f o g would nt it be h(f(x)(g(x))
h o f is h(f(x)) and then there's o g so wouldnt it be h(f(x)(g(x))
Well, h o f o g = h( f( g(x) ) ) Basically (h o f) o g is same since h and f go first anyway.
ah ok thanks

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