A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
HELP PLEASE!!!:
f(x)=3x4
g(x)=x^2
1.(f o g)(2)
2.(f o f)(2)
f(x)=2x
g(x)=x^2+2
h(x)=4x+3
1.(h o f)o g
 2 years ago
HELP PLEASE!!!: f(x)=3x4 g(x)=x^2 1.(f o g)(2) 2.(f o f)(2) f(x)=2x g(x)=x^2+2 h(x)=4x+3 1.(h o f)o g

This Question is Closed

Mathhelp346
 2 years ago
Best ResponseYou've already chosen the best response.0for the first part, what does the 2 do? i know how to solve (f o g)(x)

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.1(f o f)(2) is basically saying f( f(2) ), in other words, in 3x4, replace x with ( 3x  4 ) so you get f o f(2) = 3( 3(2)  4 )  4 then simplify.

Mathhelp346
 2 years ago
Best ResponseYou've already chosen the best response.0and how would i do the second part?

Mathhelp346
 2 years ago
Best ResponseYou've already chosen the best response.0like h(f(x)(g(x))? but then how do i solve it

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.1(h o f)(x) = h(f(x)) so (h o f)o g = h(f(x)) o g = h( f ( g(x) ) ) f(g(x)) = 2(x^2+2) so h ( f ( g ( x ) ) ) = 4(2(x^2+2) )+3 Is this clear enough?

Mathhelp346
 2 years ago
Best ResponseYou've already chosen the best response.0wait but if f o g would nt it be h(f(x)(g(x))

Mathhelp346
 2 years ago
Best ResponseYou've already chosen the best response.0h o f is h(f(x)) and then there's o g so wouldnt it be h(f(x)(g(x))

micahwood50
 2 years ago
Best ResponseYou've already chosen the best response.1Well, h o f o g = h( f( g(x) ) ) Basically (h o f) o g is same since h and f go first anyway.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.