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 2 years ago
A mass of 1kg on an incline of 37 degrees is being pulled with a force of 12 N upward that incline. The mass is attached to a string going to the bottom of the incline, which is attached to a pulley, which is attached to a string attached to a mass of 3kg on the ground. Assuming there is no friction and the mass of the string and pulley are negligible, what is the tension of the string?
 2 years ago
A mass of 1kg on an incline of 37 degrees is being pulled with a force of 12 N upward that incline. The mass is attached to a string going to the bottom of the incline, which is attached to a pulley, which is attached to a string attached to a mass of 3kg on the ground. Assuming there is no friction and the mass of the string and pulley are negligible, what is the tension of the string?

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KrisConnett
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1349917367041:dw

maheshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350795258686:dw

maheshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350795463231:dw

maheshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0For 3kg block \[T = m_1a \space \space \space \space \space \space ..........(i)eq.\]\[m_1=3kg.\]We would ignore Normal reaction & its weight because they balance each other. So no acceleration in ydirection. But there is acceleration in xdirection so we have made above equation.

maheshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0Here is Force diagram of 1kg block dw:1350796181544:dw

maheshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0here also normal & m2g cos theta would balance each other. Therefore no need of them. we need only xdirection forces because acceleration is only in xdirection. So our next equation is \[12(T+m_2g \sin \theta)= m_2a \space \space \space \space \space ..........(ii)eq.\]\[m_2=1kg.\]

maheshmeghwal9
 2 years ago
Best ResponseYou've already chosen the best response.0Now u know all the values because they are given in the question itself. So solve eq. (i) & (ii). U will get T which is the tension in the rope. But \[\LARGE{\color{red}{\text{Please read slowly all the stuff.}}}\] Thanx:)
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