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NY,NY
Group Title
HELPPP ME STUDY! solve algebraically for a and b and check:
3a+5b=4
4a+3b=2
 one year ago
 one year ago
NY,NY Group Title
HELPPP ME STUDY! solve algebraically for a and b and check: 3a+5b=4 4a+3b=2
 one year ago
 one year ago

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goformit100 Group TitleBest ResponseYou've already chosen the best response.0
You can use Matrix method for solving these two equations simultaneously
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
i only know substitution, graphing, and elimination method and those are the only methods i can use.
 one year ago

darkprince14 Group TitleBest ResponseYou've already chosen the best response.0
try eliminating either a or b
 one year ago

darkprince14 Group TitleBest ResponseYou've already chosen the best response.0
If you're looking for the point of intersection or the solution to those two then that's helpful if not, sorry, i have no clue what to do next ..
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
i need to find the value of a and b, not find the solution. like get a or b by itself.
 one year ago

darkprince14 Group TitleBest ResponseYou've already chosen the best response.0
how about let a = 0 or something like that...
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
not working :(
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Here's the plan; try to "get a in terms of b" (or "b in terms of a"). Really, I mean try to solve for a, so that it equals something that involves b (or solve for b so that it equals something that involves a).
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
yeah, i know. but how do i do that?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
You can look at either equation, and solve for either variable. It's up to you!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
It's all fair game in this problem. So pick and equation and pick a variable to solve for!
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
ok, 3a+5b=4. let's solve for a.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Okay, you start! I'll watch.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Unless you want to workon it together now; we can do that.
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
yeah, let's work on it together.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Alright. When equations aren't too complex, a great starting point is getting the terms containing variable you're solving for, a, on the opposite side of all the other terms. So look at 3a+5b=4. Which term (containing a) do we want to it's own side?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I agree! And it's with 5b, which we need to get rid of. And it appears you know how to do that! Good! So now a is still stuck with something; it's being multiplied by 3! So can you fix that, too?
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
\[a= \frac{ 5b+4 }{ 3 }\]
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
close! You forgot your sign of 5b! You had it right before! I'm guessing you were distracted by Open Study's fancy equation thing, but I don't know.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
so a=(5b+4)/3
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
oopssss. i meant 5b*
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[a=\frac{5b+4}{3}\]Haha, that's fine! So we solved for a in that one equation, 3a+5b=4. a is always a is always (5b+4)/3. So we can substitute it into another a's place. Try it in the other equation, 4a+3b=2. the a will be replaced and the only variable in the equation will be b. The we can solve for b!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
So, start by substitution!
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
20b+16/3+3b=2
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Make sure you type (20b+16)/3 + 3b = 2 ! I see you factored correctly, but the way you wrote it it didn't look like it was all divided by 3, though it really was! :)
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
So\[\frac{20b+16}{3}+3b = 2\]
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
multiply by 3?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Yeah, I'd do that!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Just so that leftmost b isn't divided by it.
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
20b+16+3b=6?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
So\[3(\frac{20b+16}{3}+3b)=3(2)\]
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Common mistake! Don't worry! You just have to remember to multiply each entire side by 3. That way you're doing the same thing to each side, so that the two new sides will still be equal.
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
i multiplied by 3 to 20b + 16 so that canceled the 3 out, and then i multiplied the 2 by 3, giving 6. what i do wrong?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
You have to multiply 3b by 3 as well!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
it becomes 9b!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
So 20b+16+9b=6 :)
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I'm sure you'll see it soon.
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
ohhh. wow, yeah. b=2?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
20b+16+9b=6 20b+9b=22 11b=22 22=11b 22/11=b 2=b Yeah!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I had to work it out to check, but we got the same thing.
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
yay :D thanks eric :D yur awesome :D
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Sorry for the wait, Open Study glitched :P Recap, we solved for "a in terms of b" and we solved for b. Now we know b and can now solve for a!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
My pleasure! Thank you for doing your part! You did great!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[a=\frac{5b+4}{3}=\frac{5(2)+4}{3}\] and compute... finale!
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
i just hope i do good on the quiz tomorrow...
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
a=10+4/3 a=6/3 a=2
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
My pleasure. Did you get a = 2?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Best of luck! Tag me in any other questions you have, or you can ask them here. But the most important thing in these an dmany other math problems is planning! Knowing what you will do. This technique we used is good for this situation.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Haha!! Caught me! 2 ! :D
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Serves me right for trying to do it in my head.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
My responses are out of order. Open Stud is scrambled, it seems.
 one year ago

NY,NY Group TitleBest ResponseYou've already chosen the best response.1
yeah. open study is being really laggy today. if i can just finish up my science homework, ill bring up some more questions to study with. thanks again :D and bye for now.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I'm glad it's not just me! No problem. Good luck with everything!
 one year ago
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