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2.A factory can produce two products, x and y, with a profit approximated by P = 14x + 22y – 900. The production of y can exceed x by no more than 200 units. Moreover, production levels are limited by the formula x + 2y ≤ 1600. What production levels yield maximum profit? x = 400; y = 600 x = 0; y = 0 x = 1,600; y = 0 x = 0; y = 200
please help you guys :/ I really need it.
I've seen this question before.
:o oh haha? Well it must have been someone from my same school then I suppose
But I really need help I've been asking these same questions for about 3 days and no one has helped :/
Okay, hang on
Hmm :o I'll wait longer haha these aren't easy questions!
it's alright thanks for taking the time (:
Man..I would have taken like a year to do it then O.o
it's alright haha you don't have to do the second one if it's going to take you too long x.x I don't wanna waste more of your time haha I feel bad, like other people need you :o
If we let: a = number of type A computers b = number of type B computers Then we can produce the following equations: Amount of Computers a + b ≤ 120 Cost of Computers: C(a,b) = 237a + 122b Profit from computers: 22a + 19b ≥ 2400
So hmm, would it be 40 of type A and 80 of B ? x.x I'm just sorta guessing here
So now we take the amount equation and the profit equation and solve for a and b: a + b ≤ 120 22a + 19b ≥ 2400 Multiply the first equation by 22 to get: 22a + 22b ≤ 2640 22a + 19b ≥ 2400 Isolate 22a in both equations: 22a ≤ 2640 - 22b 22a ≥ 2400 - 19b Now set: 22a ≤ 22a 2400 - 19b ≤ 2640 - 22b Place like terms on the same side: 22b - 19b ≤ 2640 - 2400 3b ≤ 240 b ≤ 240/3 b ≤ 80 Thus a ≤ 40 since we know that a + b ≤ 120
er man, I'm terrible at this..
Wow you figured it out
oh did I O.o
That seemed so long and complicated x.x
I'm trying to figure out what you did, lol
I already posted my steps
I just guessed to be honest I'm kind of a lucky guesser x.x
I think you did some plug and play to figure it out. You already had answer choices.
I really should learn how to do it though since I can't guess right every time haha
I, on the other hand, figured it out the hard way. It was very toilsome.
I really didn't lol I just sat and stared at the answers for while.. x.x
After trying and failing miserably, But I do think there's a quicker way :/ Just can't think of what it is at all :/
Believe it or not, what I posted IS the easy way. Good luck finding an easier way.
Haha well your really good at math and I'm super jealous >.< But I appreciate the work!
oh goodness... haha yeh I guess, so how shall I go about this second question?
Well from looking at the answers, it will be either A or D. And if I had to guess, I would guess A
Matter of fact, I'm just going to say the answer is A
without doing any work
Your guess is better than mine haha! I'll try it I suppose .
Graph the system of constraints and find the value of x and y that maximize the objective function. Objective function: C = 7x – 3y (2.5, 2.5) (0, 2) (0, 0) (5, 0)
Any ideas on this one? It's the last one I have no idea about :/ ?
Well basically we have to find the coordinates the yield the maximum value of C. This is an easy one too.
All you have to do is just plug the values into the formula
There's one obvious one that works
c'mon Megan, think outside the box. Which set of coordinates can you plug into the function to yield the highest value of C?
Sorry I was in the shower O.o
Nothing is ever easy for me :P Math is like a foriegn language to me :/
The...first one lol?
er the 4th one ... erm, I'm so dumb x.x
You must be doing something now lol...
Yes, it is the 4th one. (5,0)
ah, that's what I thought :P But I just didn't know for sure x.x I didn't really give that question much thought I guess haha