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appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ x ^{4} 16 }{x ^{2} 2 }\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0wait, is that x^2 2 ?? if yes, there is no need to factor. just put x=2

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0mm maybe do this: x[x^(3) ] +16 ooh i was wrong, is x^(2)  4

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0x^4 16 now 16 is 4^2 , isn't it ? so you can write numerator as \(\large (x^2)^24^2\) use a^2b^2 = .... formula, do u know ?

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0mm i dont remember! but once i have the numerator like that what can i do next?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0\(\large a^2b^2=(a+b)(ab) \\ \text {so what is} (x^2)^24^2 \)

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0so i'll get (x+2)^(2) * ( x2)^(2) ???

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0?? no. \(\huge (x^2)^24^2=(x^2+4)(x^24)\)

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0ooh!! i understand now ! :D so then i can cancel x^(2)  4 and the limit will be 8 right?

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0Wow! you're awesome !! :D mm what about this one? \[\frac{ \frac{ 1 }{ x } + \frac{ 1 }{ 2 }}{ x2 }\] x>2

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0that limit does not exist!

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0u know the how to find lim x>2+ and lim x>2 or know what they are ?
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