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Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1349927470125:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I can easily find the derivative of the ln(x+ln(x+ln(x))) but I cant figure out how to find the derivative of the first part.
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
i think it will be better to take the log of that part with the respect of e base.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1349927833215:dw
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
dw:1349927846691:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Okay I had an idea about that. But don't you have to do that for the ln(x+ln(x+ln(x))) as well?
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Like I thought you had to take the log of both sides for logarithmic differentiation.
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
yes,or you may solve the two parts one by one
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
So I thought you had to:dw:1349927977970:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Do you do that?
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
and even if you take the ln of ln(x+ln(x+ln(x))),there ain't any problem
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Yes yes. I knew that. But is that valid? I though you had to Log both sides of the ENTIRE term.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Ohh? Why not?
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
How is it valid? Sorry for being stubborn.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
sorry to interrupt. but ln(A+B)\(\ne\)ln A + ln B so here you have to differentiate 1st term separately , using ln
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Ohh I know @hartnn . I didn't seperate it.
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
dw:1349928327564:dw
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
that is why you can find the derivatives separately
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Lol I know. By I mean why can you ln only the (arcsin)^Tan(x)? I though you had to ln EVERYTHING.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
"had to" <no
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
why?? if you solve them part by part, you are free to take the ln of one part without changing the other
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Ohh. Okay. That explains it.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Fair enough haha...
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Could I do this instead? dw:1349928628192:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
For the derivative I mean.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
@sritama ,@hartnn
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
NO! what have u done!!
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
i couldn't get it @Dido525 :(
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
You make me chukle @hartnn .
 2 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.2
how and why will you do that?
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Well the derivative of a^x = a^x *ln(a)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
ln y = tan x ln(sin^1 (x)) diff. this. no other way
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Okay okay :P .
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Then this question isn't so hard.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
is it ? what u get as y' ?
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Doing it now.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I got: dw:1349929346410:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
For the derivative of (sin1(x))^(tan(x))
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
seems correct.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Okay :D . Thanks!
 2 years ago
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