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Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0I can easily find the derivative of the ln(x+ln(x+ln(x))) but I cant figure out how to find the derivative of the first part.

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2i think it will be better to take the log of that part with the respect of e base.

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Okay I had an idea about that. But don't you have to do that for the ln(x+ln(x+ln(x))) as well?

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Like I thought you had to take the log of both sides for logarithmic differentiation.

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2yes,or you may solve the two parts one by one

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0So I thought you had to:dw:1349927977970:dw

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2and even if you take the ln of ln(x+ln(x+ln(x))),there ain't any problem

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Yes yes. I knew that. But is that valid? I though you had to Log both sides of the ENTIRE term.

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0How is it valid? Sorry for being stubborn.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0sorry to interrupt. but ln(A+B)\(\ne\)ln A + ln B so here you have to differentiate 1st term separately , using ln

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Ohh I know @hartnn . I didn't seperate it.

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2that is why you can find the derivatives separately

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Lol I know. By I mean why can you ln only the (arcsin)^Tan(x)? I though you had to ln EVERYTHING.

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2why?? if you solve them part by part, you are free to take the ln of one part without changing the other

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Ohh. Okay. That explains it.

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Could I do this instead? dw:1349928628192:dw

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0For the derivative I mean.

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2i couldn't get it @Dido525 :(

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0You make me chukle @hartnn .

sritama
 2 years ago
Best ResponseYou've already chosen the best response.2how and why will you do that?

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Well the derivative of a^x = a^x *ln(a)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0ln y = tan x ln(sin^1 (x)) diff. this. no other way

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Then this question isn't so hard.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0is it ? what u get as y' ?

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0I got: dw:1349929346410:dw

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0For the derivative of (sin1(x))^(tan(x))
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