At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I can easily find the derivative of the ln(x+ln(x+ln(x))) but I cant figure out how to find the derivative of the first part.
i think it will be better to take the log of that part with the respect of e base.
Okay I had an idea about that. But don't you have to do that for the ln(x+ln(x+ln(x))) as well?
Like I thought you had to take the log of both sides for logarithmic differentiation.
yes,or you may solve the two parts one by one
So I thought you had to:|dw:1349927977970:dw|
Do you do that?
and even if you take the ln of ln(x+ln(x+ln(x))),there ain't any problem
Yes yes. I knew that. But is that valid? I though you had to Log both sides of the ENTIRE term.
Ohh? Why not?
yes it is.
How is it valid? Sorry for being stubborn.
sorry to interrupt. but ln(A+B)\(\ne\)ln A + ln B so here you have to differentiate 1st term separately , using ln
Ohh I know @hartnn . I didn't seperate it.
that is why you can find the derivatives separately
Lol I know. By I mean why can you ln only the (arcsin)^Tan(x)? I though you had to ln EVERYTHING.
"had to" <---no
why?? if you solve them part by part, you are free to take the ln of one part without changing the other
Ohh. Okay. That explains it.
Fair enough haha...
Could I do this instead? |dw:1349928628192:dw|
For the derivative I mean.
NO! what have u done!!
i couldn't get it @Dido525 :(
You make me chukle @hartnn .
how and why will you do that?
Well the derivative of a^x = a^x *ln(a)
ln y = tan x ln(sin^-1 (x)) diff. this. no other way
Okay okay :P .
Then this question isn't so hard.
is it ? what u get as y' ?
Doing it now.
I got: |dw:1349929346410:dw|
For the derivative of (sin-1(x))^(tan(x))
Okay :D . Thanks!