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Dido525Best ResponseYou've already chosen the best response.0
I can easily find the derivative of the ln(x+ln(x+ln(x))) but I cant figure out how to find the derivative of the first part.
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
i think it will be better to take the log of that part with the respect of e base.
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Okay I had an idea about that. But don't you have to do that for the ln(x+ln(x+ln(x))) as well?
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Like I thought you had to take the log of both sides for logarithmic differentiation.
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
yes,or you may solve the two parts one by one
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
So I thought you had to:dw:1349927977970:dw
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
and even if you take the ln of ln(x+ln(x+ln(x))),there ain't any problem
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Yes yes. I knew that. But is that valid? I though you had to Log both sides of the ENTIRE term.
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
How is it valid? Sorry for being stubborn.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
sorry to interrupt. but ln(A+B)\(\ne\)ln A + ln B so here you have to differentiate 1st term separately , using ln
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Ohh I know @hartnn . I didn't seperate it.
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
that is why you can find the derivatives separately
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Lol I know. By I mean why can you ln only the (arcsin)^Tan(x)? I though you had to ln EVERYTHING.
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
why?? if you solve them part by part, you are free to take the ln of one part without changing the other
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Ohh. Okay. That explains it.
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Could I do this instead? dw:1349928628192:dw
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
For the derivative I mean.
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
i couldn't get it @Dido525 :(
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
You make me chukle @hartnn .
 one year ago

sritamaBest ResponseYou've already chosen the best response.2
how and why will you do that?
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Well the derivative of a^x = a^x *ln(a)
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
ln y = tan x ln(sin^1 (x)) diff. this. no other way
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
Then this question isn't so hard.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
is it ? what u get as y' ?
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
I got: dw:1349929346410:dw
 one year ago

Dido525Best ResponseYou've already chosen the best response.0
For the derivative of (sin1(x))^(tan(x))
 one year ago
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