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blackrose636
 2 years ago
find d^2(y)/d(x^2) in terms of x and y (second derivative)
1xy=xy
blackrose636
 2 years ago
find d^2(y)/d(x^2) in terms of x and y (second derivative) 1xy=xy

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VeritasVosLiberabit
 2 years ago
Best ResponseYou've already chosen the best response.1\[1(\frac{ dy }{ dx })(x)\frac{ dy }{ dx}+\frac{ dx }{dx }y=\frac{ dx }{ dx }\frac{ dy }{ dx }\] tell me how this looks it's been a while since I differentiated with this method.

VeritasVosLiberabit
 2 years ago
Best ResponseYou've already chosen the best response.1this would be the setup to solve for the first derivative

VeritasVosLiberabit
 2 years ago
Best ResponseYou've already chosen the best response.1mother of god...

blackrose636
 2 years ago
Best ResponseYou've already chosen the best response.0how did u get the second derivative? @mahmit2012

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0( x*y' + y) = 1 y'

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0differentiate the expression again

VeritasVosLiberabit
 2 years ago
Best ResponseYou've already chosen the best response.1I didn't do the second derivative yet. just do the first then repeat.

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0if you get another y' in your expression for y" sub.s in your result from the first differentiation...

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0Does that make sense?

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.1y=1 y"=0 why you did not pay attention!

blackrose636
 2 years ago
Best ResponseYou've already chosen the best response.0i got y' is y1/x1 then i tried doing quotient rule and thne i got confused

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0you fail at math @mahmit2012

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.1every body sleeping !! cool

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0now, f = ( y1) g = (x1) (f/g)' = f'g fg'/g^2 f' = y' g' = 1 g^2 = (x1)^2

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0plug them in and use the result from the first diff. : y' = y1/x1 to sub.s in for y'

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.1find y=1 it's so easy !!!

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.0got it @blackrose636 ?

blackrose636
 2 years ago
Best ResponseYou've already chosen the best response.0how did u even get y=1?

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.1yxy=x1 so y=1 for all x#1

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.1@Algebraic! did you get it !

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.2Ah... 1  xy = xy yxy = x1 y (1x) = x1 y = (x1) / (1x) y=1!

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.1this is different seeing !
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