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find d^2(y)/d(x^2) in terms of x and y (second derivative)
1xy=xy
 one year ago
 one year ago
find d^2(y)/d(x^2) in terms of x and y (second derivative) 1xy=xy
 one year ago
 one year ago

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VeritasVosLiberabitBest ResponseYou've already chosen the best response.1
\[1(\frac{ dy }{ dx })(x)\frac{ dy }{ dx}+\frac{ dx }{dx }y=\frac{ dx }{ dx }\frac{ dy }{ dx }\] tell me how this looks it's been a while since I differentiated with this method.
 one year ago

VeritasVosLiberabitBest ResponseYou've already chosen the best response.1
this would be the setup to solve for the first derivative
 one year ago

VeritasVosLiberabitBest ResponseYou've already chosen the best response.1
mother of god...
 one year ago

blackrose636Best ResponseYou've already chosen the best response.0
how did u get the second derivative? @mahmit2012
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
( x*y' + y) = 1 y'
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
differentiate the expression again
 one year ago

VeritasVosLiberabitBest ResponseYou've already chosen the best response.1
I didn't do the second derivative yet. just do the first then repeat.
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
if you get another y' in your expression for y" sub.s in your result from the first differentiation...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
Does that make sense?
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
y=1 y"=0 why you did not pay attention!
 one year ago

blackrose636Best ResponseYou've already chosen the best response.0
i got y' is y1/x1 then i tried doing quotient rule and thne i got confused
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
you fail at math @mahmit2012
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
every body sleeping !! cool
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
now, f = ( y1) g = (x1) (f/g)' = f'g fg'/g^2 f' = y' g' = 1 g^2 = (x1)^2
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
plug them in and use the result from the first diff. : y' = y1/x1 to sub.s in for y'
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
find y=1 it's so easy !!!
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
got it @blackrose636 ?
 one year ago

blackrose636Best ResponseYou've already chosen the best response.0
how did u even get y=1?
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
yxy=x1 so y=1 for all x#1
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
@Algebraic! did you get it !
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
Ah... 1  xy = xy yxy = x1 y (1x) = x1 y = (x1) / (1x) y=1!
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
Thank you @Callisto
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
this is different seeing !
 one year ago
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