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blackrose636

  • 3 years ago

find d^2(y)/d(x^2) in terms of x and y (second derivative) 1-xy=x-y

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  1. VeritasVosLiberabit
    • 3 years ago
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    \[1(\frac{ dy }{ dx })-(x)\frac{ dy }{ dx}+\frac{ dx }{dx }y=\frac{ dx }{ dx }-\frac{ dy }{ dx }\] tell me how this looks it's been a while since I differentiated with this method.

  2. VeritasVosLiberabit
    • 3 years ago
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    this would be the setup to solve for the first derivative

  3. mahmit2012
    • 3 years ago
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    y=-1 & y"=0

  4. Algebraic!
    • 3 years ago
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    http://i.imgur.com/CMgMz.gif

  5. VeritasVosLiberabit
    • 3 years ago
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    mother of god...

  6. blackrose636
    • 3 years ago
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    how did u get the second derivative? @mahmit2012

  7. Algebraic!
    • 3 years ago
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    -( x*y' + y) = 1 -y'

  8. Algebraic!
    • 3 years ago
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    solve for y'

  9. Algebraic!
    • 3 years ago
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    differentiate the expression again

  10. VeritasVosLiberabit
    • 3 years ago
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    I didn't do the second derivative yet. just do the first then repeat.

  11. Algebraic!
    • 3 years ago
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    if you get another y' in your expression for y" sub.s in your result from the first differentiation...

  12. Algebraic!
    • 3 years ago
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    Does that make sense?

  13. mahmit2012
    • 3 years ago
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    y=-1 y"=0 why you did not pay attention!

  14. mahmit2012
    • 3 years ago
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    x#1

  15. blackrose636
    • 3 years ago
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    i got y' is -y-1/x-1 then i tried doing quotient rule and thne i got confused

  16. Algebraic!
    • 3 years ago
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    you fail at math @mahmit2012

  17. Algebraic!
    • 3 years ago
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    k

  18. Algebraic!
    • 3 years ago
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    you got y' right

  19. mahmit2012
    • 3 years ago
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    every body sleeping !! cool

  20. blackrose636
    • 3 years ago
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    yeah -y-1/x-1

  21. Algebraic!
    • 3 years ago
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    now, f = ( -y-1) g = (x-1) (f/g)' = f'g -fg'/g^2 f' = -y' g' = 1 g^2 = (x-1)^2

  22. Algebraic!
    • 3 years ago
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    plug them in and use the result from the first diff. : y' = -y-1/x-1 to sub.s in for y'

  23. mahmit2012
    • 3 years ago
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    find y=-1 it's so easy !!!

  24. Algebraic!
    • 3 years ago
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    got it @blackrose636 ?

  25. blackrose636
    • 3 years ago
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    how did u even get y=-1?

  26. Algebraic!
    • 3 years ago
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    gl @Callisto

  27. mahmit2012
    • 3 years ago
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    y-xy=x-1 so y=-1 for all x#1

  28. mahmit2012
    • 3 years ago
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    @Algebraic! did you get it !

  29. Callisto
    • 3 years ago
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    Ah... 1 - xy = x-y y-xy = x-1 y (1-x) = x-1 y = (x-1) / (1-x) y=-1!

  30. mahmit2012
    • 3 years ago
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    Thank you @Callisto

  31. mahmit2012
    • 3 years ago
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    this is different seeing !

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