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this would be the setup to solve for the first derivative

y=-1 & y"=0

http://i.imgur.com/CMgMz.gif

mother of god...

how did u get the second derivative?
@mahmit2012

-( x*y' + y) = 1 -y'

solve for y'

differentiate the expression again

I didn't do the second derivative yet. just do the first then repeat.

Does that make sense?

y=-1 y"=0 why you did not pay attention!

x#1

i got y' is -y-1/x-1
then i tried doing quotient rule and thne i got confused

you fail at math @mahmit2012

you got y' right

every body sleeping !! cool

yeah -y-1/x-1

now, f = ( -y-1) g = (x-1)
(f/g)' = f'g -fg'/g^2
f' = -y'
g' = 1
g^2 = (x-1)^2

plug them in and use the result from the first diff. : y' = -y-1/x-1
to sub.s in for y'

find y=-1 it's so easy !!!

got it @blackrose636 ?

how did u even get y=-1?

y-xy=x-1
so y=-1 for all x#1

@Algebraic! did you get it !

Ah...
1 - xy = x-y
y-xy = x-1
y (1-x) = x-1
y = (x-1) / (1-x)
y=-1!

this is different seeing !