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blackrose636
Group Title
find d^2(y)/d(x^2) in terms of x and y (second derivative)
1xy=xy
 2 years ago
 2 years ago
blackrose636 Group Title
find d^2(y)/d(x^2) in terms of x and y (second derivative) 1xy=xy
 2 years ago
 2 years ago

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VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.1
\[1(\frac{ dy }{ dx })(x)\frac{ dy }{ dx}+\frac{ dx }{dx }y=\frac{ dx }{ dx }\frac{ dy }{ dx }\] tell me how this looks it's been a while since I differentiated with this method.
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.1
this would be the setup to solve for the first derivative
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
y=1 & y"=0
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.1
mother of god...
 2 years ago

blackrose636 Group TitleBest ResponseYou've already chosen the best response.0
how did u get the second derivative? @mahmit2012
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
( x*y' + y) = 1 y'
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
solve for y'
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
differentiate the expression again
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.1
I didn't do the second derivative yet. just do the first then repeat.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
if you get another y' in your expression for y" sub.s in your result from the first differentiation...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
Does that make sense?
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
y=1 y"=0 why you did not pay attention!
 2 years ago

blackrose636 Group TitleBest ResponseYou've already chosen the best response.0
i got y' is y1/x1 then i tried doing quotient rule and thne i got confused
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
you fail at math @mahmit2012
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
you got y' right
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
every body sleeping !! cool
 2 years ago

blackrose636 Group TitleBest ResponseYou've already chosen the best response.0
yeah y1/x1
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
now, f = ( y1) g = (x1) (f/g)' = f'g fg'/g^2 f' = y' g' = 1 g^2 = (x1)^2
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
plug them in and use the result from the first diff. : y' = y1/x1 to sub.s in for y'
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
find y=1 it's so easy !!!
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
got it @blackrose636 ?
 2 years ago

blackrose636 Group TitleBest ResponseYou've already chosen the best response.0
how did u even get y=1?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
gl @Callisto
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
yxy=x1 so y=1 for all x#1
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
@Algebraic! did you get it !
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
Ah... 1  xy = xy yxy = x1 y (1x) = x1 y = (x1) / (1x) y=1!
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
Thank you @Callisto
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
this is different seeing !
 2 years ago
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