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what is the limit for the next function?

Mathematics
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\[\frac{ (3+h)^{-1} - 3^{-1}}{h }\]
h ---> 0
you try a manipulation of L'hospital???????

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Other answers:

you have an indeterminate of \[\frac{ 0 }{0 }\] I would try l'hopital's rule
mm i dont know how!
I'm assuming h is just a variable that can be treated like x. just take the derivative of the top portion and the derivative of the bottom and see if you can find a limit as h->0
actually you may not have an indeterminate of \[\frac{ 0 }{ 0 }\]
\[\lim_{h \rightarrow 0}\frac{ 1 }{ h[(3+h)-3] }\]
but ho did we get the 1 in the numerator?
how*
I just rearranged the equation not sure exactly what to do next. Not sure what the question means by "next function"
mmm yaa, i dont know how to solve it !, my teacher doesnt allow me to derivate the function so i dont know what he want me to solve it :/
how* instead of what haha >.< :/

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