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appleduardo Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ (3+h)^{1}  3^{1}}{h }\]
 2 years ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
h > 0
 2 years ago

chemENGINEER Group TitleBest ResponseYou've already chosen the best response.0
you try a manipulation of L'hospital???????
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
you have an indeterminate of \[\frac{ 0 }{0 }\] I would try l'hopital's rule
 2 years ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
mm i dont know how!
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
I'm assuming h is just a variable that can be treated like x. just take the derivative of the top portion and the derivative of the bottom and see if you can find a limit as h>0
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
actually you may not have an indeterminate of \[\frac{ 0 }{ 0 }\]
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{h \rightarrow 0}\frac{ 1 }{ h[(3+h)3] }\]
 2 years ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
but ho did we get the 1 in the numerator?
 2 years ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
I just rearranged the equation not sure exactly what to do next. Not sure what the question means by "next function"
 2 years ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
mmm yaa, i dont know how to solve it !, my teacher doesnt allow me to derivate the function so i dont know what he want me to solve it :/
 2 years ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
how* instead of what haha >.< :/
 2 years ago
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