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appleduardo Group Title

what is the limit for the next function?

  • 2 years ago
  • 2 years ago

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  1. appleduardo Group Title
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    \[\frac{ (3+h)^{-1} - 3^{-1}}{h }\]

    • 2 years ago
  2. appleduardo Group Title
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    h ---> 0

    • 2 years ago
  3. chemENGINEER Group Title
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    you try a manipulation of L'hospital???????

    • 2 years ago
  4. VeritasVosLiberabit Group Title
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    you have an indeterminate of \[\frac{ 0 }{0 }\] I would try l'hopital's rule

    • 2 years ago
  5. appleduardo Group Title
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    mm i dont know how!

    • 2 years ago
  6. VeritasVosLiberabit Group Title
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    I'm assuming h is just a variable that can be treated like x. just take the derivative of the top portion and the derivative of the bottom and see if you can find a limit as h->0

    • 2 years ago
  7. VeritasVosLiberabit Group Title
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    actually you may not have an indeterminate of \[\frac{ 0 }{ 0 }\]

    • 2 years ago
  8. VeritasVosLiberabit Group Title
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    \[\lim_{h \rightarrow 0}\frac{ 1 }{ h[(3+h)-3] }\]

    • 2 years ago
  9. appleduardo Group Title
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    but ho did we get the 1 in the numerator?

    • 2 years ago
  10. appleduardo Group Title
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    how*

    • 2 years ago
  11. VeritasVosLiberabit Group Title
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    I just rearranged the equation not sure exactly what to do next. Not sure what the question means by "next function"

    • 2 years ago
  12. appleduardo Group Title
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    mmm yaa, i dont know how to solve it !, my teacher doesnt allow me to derivate the function so i dont know what he want me to solve it :/

    • 2 years ago
  13. appleduardo Group Title
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    how* instead of what haha >.< :/

    • 2 years ago
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spraguer (Moderator)
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