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appleduardo Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ (3+h)^{1}  3^{1}}{h }\]
 one year ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
h > 0
 one year ago

chemENGINEER Group TitleBest ResponseYou've already chosen the best response.0
you try a manipulation of L'hospital???????
 one year ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
you have an indeterminate of \[\frac{ 0 }{0 }\] I would try l'hopital's rule
 one year ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
mm i dont know how!
 one year ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
I'm assuming h is just a variable that can be treated like x. just take the derivative of the top portion and the derivative of the bottom and see if you can find a limit as h>0
 one year ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
actually you may not have an indeterminate of \[\frac{ 0 }{ 0 }\]
 one year ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{h \rightarrow 0}\frac{ 1 }{ h[(3+h)3] }\]
 one year ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
but ho did we get the 1 in the numerator?
 one year ago

VeritasVosLiberabit Group TitleBest ResponseYou've already chosen the best response.0
I just rearranged the equation not sure exactly what to do next. Not sure what the question means by "next function"
 one year ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
mmm yaa, i dont know how to solve it !, my teacher doesnt allow me to derivate the function so i dont know what he want me to solve it :/
 one year ago

appleduardo Group TitleBest ResponseYou've already chosen the best response.0
how* instead of what haha >.< :/
 one year ago
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