anonymous
  • anonymous
The position of a mass on a spring (relative to equilibrium) at time t <= 0 is x(t) = 2 cos((pi)t) where x is in centimeters and t is in seconds. Answer the ques- tions. Include units! (a) What is the initial position of the mass? (b) What is the initial velocity of the mass? (c) What is the initial acceleration of the mass? (d) Does the mass initially move towards the wall or away from it? (e) At what point does the mass rst turn around?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
goformit100
  • goformit100
post the question in physics section Not here @GrizzlyChicken
anonymous
  • anonymous
its in my calc book, isn't this math?
anonymous
  • anonymous
a) put t = 0 and solve for x b) find x' and put t = 0 and solve for x' c) find x'' and put y = 0 and solve for x''

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
it's both physics and math lol
anonymous
  • anonymous
*typo fix* sorry c) find x'' and put t=0
anonymous
  • anonymous
wait, its x(t)=2cos((pi)(t))
anonymous
  • anonymous
sorry
anonymous
  • anonymous
still~ same way of solving :P
anonymous
  • anonymous
damn, theres another error, i'm gonna look it all over again, for some reason copy and pasting changed everything
anonymous
  • anonymous
at time t is greater or equal to 0. its right now
anonymous
  • anonymous
so if i put 0 for t, its 2cos(0)
anonymous
  • anonymous
yup, that's the initial position
anonymous
  • anonymous
is cos(0)=1?
anonymous
  • anonymous
yes
anonymous
  • anonymous
then for b) derivative of 2 is 0 so its all 0
anonymous
  • anonymous
maybe
anonymous
  • anonymous
no no, find the derivative of the function x
anonymous
  • anonymous
so the derivative of 2cos(pi*0)?
anonymous
  • anonymous
which uses the product rule (0)(cos...)+(2)(-sin(0))
anonymous
  • anonymous
and sin(0)=0
anonymous
  • anonymous
so the velocity is 0
anonymous
  • anonymous
wops sorry i'm here x = 2 cos (pi t) x' = -2 pi sin (pi t)
anonymous
  • anonymous
do you know how to derivative?
anonymous
  • anonymous
yea, did you use the chain rule?
anonymous
  • anonymous
is that why pi is with -2?
anonymous
  • anonymous
no chain rule. derivative of cos is -sin. pi 's brought out when derivative.
anonymous
  • anonymous
|dw:1349943924669:dw|
anonymous
  • anonymous
derivative again for the acceleration equation
anonymous
  • anonymous
-2cos(pi*t)
anonymous
  • anonymous
wait
anonymous
  • anonymous
-2pi*cos(pi*t)
anonymous
  • anonymous
almost correct, but now pi is brought one more time so it's -2 pi^2 cos (pi t)
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
x = 2 cos (pi t) x0 = 2 x' = v = -2 pi sin (pi t) v0 = 0 x'' = a = -2 pi^2 cos (pi t) a0 = -2pi^2 and idk how to do d and e
anonymous
  • anonymous
does the mass move toward the wall because the acceleration is negative?
anonymous
  • anonymous
oh, thats alright. you've helped me enough.Thanks!

Looking for something else?

Not the answer you are looking for? Search for more explanations.