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post the question in physics section Not here @GrizzlyChicken
its in my calc book, isn't this math?
a) put t = 0 and solve for x b) find x' and put t = 0 and solve for x' c) find x'' and put y = 0 and solve for x''
it's both physics and math lol
*typo fix* sorry c) find x'' and put t=0
wait, its x(t)=2cos((pi)(t))
still~ same way of solving :P
damn, theres another error, i'm gonna look it all over again, for some reason copy and pasting changed everything
at time t is greater or equal to 0. its right now
so if i put 0 for t, its 2cos(0)
yup, that's the initial position
then for b) derivative of 2 is 0 so its all 0
no no, find the derivative of the function x
so the derivative of 2cos(pi*0)?
which uses the product rule (0)(cos...)+(2)(-sin(0))
so the velocity is 0
wops sorry i'm here x = 2 cos (pi t) x' = -2 pi sin (pi t)
do you know how to derivative?
yea, did you use the chain rule?
is that why pi is with -2?
no chain rule. derivative of cos is -sin. pi 's brought out when derivative.
derivative again for the acceleration equation
almost correct, but now pi is brought one more time so it's -2 pi^2 cos (pi t)
x = 2 cos (pi t) x0 = 2 x' = v = -2 pi sin (pi t) v0 = 0 x'' = a = -2 pi^2 cos (pi t) a0 = -2pi^2 and idk how to do d and e
does the mass move toward the wall because the acceleration is negative?
oh, thats alright. you've helped me enough.Thanks!