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my code is off by 10 compared to other test cases, but not all the time, any ideas? balance = 4157 annualInterestRate = 0.18 payment = 10 def payforyear(x): count = 0 while count < 12: x = (x - payment) + (x*(annualInterestRate / 12)) count = count + 1 if count == 12: return x while payforyear(balance) > 0: payment = payment + 10 else: print ('Lowest payment: ' +str(payment) )

MIT 6.00 Intro Computer Science (OCW)
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Why do you check if count == 12? Since the while loop will end anyway when the count reaches 12, you can just return the value!
if i recall correctly, if i didn't check count 12 and put the return x line in it returned the result after one iteration of the loop
Well, the main thing that is wrong is the formula (x-paymnet)+(x*(annualInterestRate/12)) If you check instructions it is (xipayment)*(1-(annualInterestRate/12)) This will fix your problem but stylistically using variables defined outside the function is bad practice unless absolutely necessary.

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Sorry just to be clear, which exercise are you trying to solve? I guess it's the second one!
That should read (x-payment)...
And (1+(... not minus
x = (x - payment) *(1+annualInterestRate / 12) should do the trick I guess
Yes, it does actually problem is I have no idea how, and why i got it wrong in the first place. I have looked at that area of the code more than a few times over the past 12 hours I have been working on it. I have this weird feeling that my solution is very very very far from other peoples solutions.
Yes and as chris said previously the if count==12 is not necessary as long as the return statement is lined up with the while, I tested it too.
yes thank you for that Chris, I am still getting my head around logic and python work flow. I was scratching my head with the while statement and indentation for a good couple of hours.
Indentation in python is very important to the meaning and this is a good reason for beginners to learn python because it forces good habits of indentation. Which isn't necessary in some languages but always recommended.
Ditto!

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