julie001
X+5 over 3 = x-3 over 4
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gaara438125
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i posted this in the other than, does it look like this?
\[\frac{ x + 5 }{ 3 } = \frac{ x - 3 }{ 4 }\]
dylan18
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what can we do with that?
julie001
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Yes
gaara438125
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find x?
julie001
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Common denominator rite?
dylan18
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ahhhhhhh!!
gaara438125
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hahahahaha julie u are truely smart :]
gaara438125
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so the lcd is obviously 12 which gets us?
julie001
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Im lost
gaara438125
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ok so the Least common denominator of 3 and 4 is 12 so you have to multiply
\[\frac{ x + 5 }{ 3 } * \frac{ 4 }{ 4 }\]
julie001
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20x over 12?
dylan18
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yah. that rite.
gaara438125
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no \[\frac{ 4x + 20}{12}\]
but i see where you could have done the 20x
julie001
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Ooo wats nxt?
dylan18
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i mean the solution
@gaara438125
gaara438125
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so the other side then becomes\[\frac{ 3x - 9 }{ 12 }\]
because we do \[\frac{ x - 3 }{ 4 } * \frac{ 3 }{ 3 }\]
so it looks like
\[\frac{ 4x + 20 }{ 12 } = \frac{ 3x - 9 }{ 12 }\]
gaara438125
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multiply both sides by 12 to get what?
julie001
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Idk hw to do that
gaara438125
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since both sides are being divided by 12 you can multiply BOTH sides to rid of the fraction leaving only \[4x + 20 = 3x - 9\]
julie001
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Do i combine like terms
gaara438125
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yes :] you are very smart i think your just not trying ;P
julie001
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I got it thanks ;)
gaara438125
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ok good