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Cherishyou
Group Title
Write the equation of the circle whose center is at the origin and whose diameter is 12.
 one year ago
 one year ago
Cherishyou Group Title
Write the equation of the circle whose center is at the origin and whose diameter is 12.
 one year ago
 one year ago

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krkista Group TitleBest ResponseYou've already chosen the best response.1
x^2 + y^2 = r^2 is the general formula for a circle with the center in [0,0] Thus, \[x^2 + y^2 = 12^2\] \[x^2 + y^2 = 144\]
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.0
\[x^2+y^2+z^2=36\]
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.0
OR \[x^2+y^2=36\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
the general form a a circle centered at \((a,b)\)\[(xa)^2+(yb)^2=r^2\]
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
This was (a little bit) of a trick question. They tell you the diameter is 12. But you need the radius, which is 1/2 of the diameter. The radius is 6
 one year ago
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