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Cherishyou

  • 3 years ago

Write the equation of the circle whose center is at the origin and whose diameter is 12.

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  1. krkista
    • 3 years ago
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    x^2 + y^2 = r^2 is the general formula for a circle with the center in [0,0] Thus, \[x^2 + y^2 = 12^2\] \[x^2 + y^2 = 144\]

  2. rvgupta
    • 3 years ago
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    \[x^2+y^2+z^2=36\]

  3. rvgupta
    • 3 years ago
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    OR \[x^2+y^2=36\]

  4. UnkleRhaukus
    • 3 years ago
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    the general form a a circle centered at \((a,b)\)\[(x-a)^2+(y-b)^2=r^2\]

  5. phi
    • 3 years ago
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    This was (a little bit) of a trick question. They tell you the diameter is 12. But you need the radius, which is 1/2 of the diameter. The radius is 6

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