anonymous
  • anonymous
HELP PEOPLE HARD MATH QUESTION :0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Simplify the expression \[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\] If the simplified expression is written in standard form, what is the leading coefficient?
across
  • across
Hint:\[3^3=27\]
anonymous
  • anonymous
so the answer is 3 lol?

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anonymous
  • anonymous
but it's a sqrt not a cubed root?
anonymous
  • anonymous
huh?
anonymous
  • anonymous
across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o
anonymous
  • anonymous
oh yea ^^
anonymous
  • anonymous
the only coefficient i see is 2
anonymous
  • anonymous
across is taking forever to answer lol
anonymous
  • anonymous
wait did we get the answer?
anonymous
  • anonymous
you just deleted that whole thing?!
UnkleRhaukus
  • UnkleRhaukus
i made an error
anonymous
  • anonymous
what ^^
UnkleRhaukus
  • UnkleRhaukus
\[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]
anonymous
  • anonymous
so thats the answer LOL
UnkleRhaukus
  • UnkleRhaukus
hmm
anonymous
  • anonymous
the last part is right?
UnkleRhaukus
  • UnkleRhaukus
maybe my second line in more useful
anonymous
  • anonymous
what do u mean?

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