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SchoolFreak

HELP PEOPLE HARD MATH QUESTION :0

  • one year ago
  • one year ago

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  1. SchoolFreak
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    Simplify the expression \[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\] If the simplified expression is written in standard form, what is the leading coefficient?

    • one year ago
  2. across
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    Hint:\[3^3=27\]

    • one year ago
  3. SchoolFreak
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    so the answer is 3 lol?

    • one year ago
  4. gaara438125
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    but it's a sqrt not a cubed root?

    • one year ago
  5. SchoolFreak
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    huh?

    • one year ago
  6. gaara438125
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    across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o

    • one year ago
  7. SchoolFreak
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    oh yea ^^

    • one year ago
  8. gaara438125
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    the only coefficient i see is 2

    • one year ago
  9. SchoolFreak
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    across is taking forever to answer lol

    • one year ago
  10. SchoolFreak
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    wait did we get the answer?

    • one year ago
  11. gaara438125
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    you just deleted that whole thing?!

    • one year ago
  12. UnkleRhaukus
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    i made an error

    • one year ago
  13. SchoolFreak
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    what ^^

    • one year ago
  14. UnkleRhaukus
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    \[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]

    • one year ago
  15. SchoolFreak
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    so thats the answer LOL

    • one year ago
  16. UnkleRhaukus
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    hmm

    • one year ago
  17. SchoolFreak
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    the last part is right?

    • one year ago
  18. UnkleRhaukus
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    maybe my second line in more useful

    • one year ago
  19. SchoolFreak
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    what do u mean?

    • one year ago
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