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SchoolFreakBest ResponseYou've already chosen the best response.0
Simplify the expression \[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\] If the simplified expression is written in standard form, what is the leading coefficient?
 one year ago

SchoolFreakBest ResponseYou've already chosen the best response.0
so the answer is 3 lol?
 one year ago

gaara438125Best ResponseYou've already chosen the best response.0
but it's a sqrt not a cubed root?
 one year ago

gaara438125Best ResponseYou've already chosen the best response.0
across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o
 one year ago

gaara438125Best ResponseYou've already chosen the best response.0
the only coefficient i see is 2
 one year ago

SchoolFreakBest ResponseYou've already chosen the best response.0
across is taking forever to answer lol
 one year ago

SchoolFreakBest ResponseYou've already chosen the best response.0
wait did we get the answer?
 one year ago

gaara438125Best ResponseYou've already chosen the best response.0
you just deleted that whole thing?!
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
\[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]
 one year ago

SchoolFreakBest ResponseYou've already chosen the best response.0
so thats the answer LOL
 one year ago

SchoolFreakBest ResponseYou've already chosen the best response.0
the last part is right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
maybe my second line in more useful
 one year ago
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