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SchoolFreak
 2 years ago
Best ResponseYou've already chosen the best response.0Simplify the expression \[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\] If the simplified expression is written in standard form, what is the leading coefficient?

SchoolFreak
 2 years ago
Best ResponseYou've already chosen the best response.0so the answer is 3 lol?

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.0but it's a sqrt not a cubed root?

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.0across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.0the only coefficient i see is 2

SchoolFreak
 2 years ago
Best ResponseYou've already chosen the best response.0across is taking forever to answer lol

SchoolFreak
 2 years ago
Best ResponseYou've already chosen the best response.0wait did we get the answer?

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.0you just deleted that whole thing?!

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.2\[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]

SchoolFreak
 2 years ago
Best ResponseYou've already chosen the best response.0so thats the answer LOL

SchoolFreak
 2 years ago
Best ResponseYou've already chosen the best response.0the last part is right?

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.2maybe my second line in more useful
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