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HELP PEOPLE HARD MATH QUESTION :0

Mathematics
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Simplify the expression \[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\] If the simplified expression is written in standard form, what is the leading coefficient?
Hint:\[3^3=27\]
so the answer is 3 lol?

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Other answers:

but it's a sqrt not a cubed root?
huh?
across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o
oh yea ^^
the only coefficient i see is 2
across is taking forever to answer lol
wait did we get the answer?
you just deleted that whole thing?!
i made an error
what ^^
\[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]
so thats the answer LOL
hmm
the last part is right?
maybe my second line in more useful
what do u mean?

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