SchoolFreak
HELP PEOPLE HARD MATH QUESTION :0
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SchoolFreak
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Simplify the expression
\[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]
If the simplified expression is written in standard form, what is the leading coefficient?
across
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Hint:\[3^3=27\]
SchoolFreak
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so the answer is 3 lol?
gaara438125
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but it's a sqrt not a cubed root?
SchoolFreak
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huh?
gaara438125
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across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o
SchoolFreak
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oh yea ^^
gaara438125
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the only coefficient i see is 2
SchoolFreak
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across is taking forever to answer lol
SchoolFreak
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wait did we get the answer?
gaara438125
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you just deleted that whole thing?!
UnkleRhaukus
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i made an error
SchoolFreak
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what ^^
UnkleRhaukus
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\[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]
SchoolFreak
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so thats the answer LOL
UnkleRhaukus
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hmm
SchoolFreak
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the last part is right?
UnkleRhaukus
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maybe my second line in more useful
SchoolFreak
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what do u mean?