## SchoolFreak 3 years ago HELP PEOPLE HARD MATH QUESTION :0

1. SchoolFreak

Simplify the expression $\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}$ If the simplified expression is written in standard form, what is the leading coefficient?

2. across

Hint:$3^3=27$

3. SchoolFreak

so the answer is 3 lol?

4. gaara438125

but it's a sqrt not a cubed root?

5. SchoolFreak

huh?

6. gaara438125

across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o

7. SchoolFreak

oh yea ^^

8. gaara438125

the only coefficient i see is 2

9. SchoolFreak

across is taking forever to answer lol

10. SchoolFreak

wait did we get the answer?

11. gaara438125

you just deleted that whole thing?!

12. UnkleRhaukus

13. SchoolFreak

what ^^

14. UnkleRhaukus

$\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}$$=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}$$=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}$$=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}$$=(x^2 + x^{1/2} + 9)\sqrt {3x}$

15. SchoolFreak

16. UnkleRhaukus

hmm

17. SchoolFreak

the last part is right?

18. UnkleRhaukus

maybe my second line in more useful

19. SchoolFreak

what do u mean?