A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0\[x{3} + 8 x{3}\]

across
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^3+8x^3=x^3(1+8)=9x^3\]

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0Cool! Here's the next one...\[15x{7}13x{7}\]

across
 2 years ago
Best ResponseYou've already chosen the best response.0Could you do the same exact thing for this one?

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.1@HorseCrazyGirlForever ok

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0\[2x{7}\]

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0( x^5) (3x^5)

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0What is the answer?

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0Cool! Here's the next one........

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0(3x^8) divided by ( x^5 )

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0Awesomeness! Here are all the rest. 5x^3+9x^37x^3 = 20x^12 10x^12  7x^12 = ( 7x^3) (2x^6 )= (18x^13 ) divided by ( 3x^7 )

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Hey! @HorseCrazyGirlForever you should be wanting to learn this. Ask questions and engage in the discussion. @mayankdevnani If the user is asking similar questions, make them do a little more work each time. Try to teach. And also please make a separate thread for each question. Thanks.

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0You don't even need to factor our the x... they have the same base so you can add / substract them.... Then you go by factoring. > simplify if you have different bases and then factor out stuff to get to your simplest form.

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0I don't really understand...

HorseCrazyGirlForever
 2 years ago
Best ResponseYou've already chosen the best response.0The ones I just posted.......

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0I am assuming all of them are different equations btw 5x^3+9x^37x^3 = 1) Simplify them by adding / substracting because of same base 7x^3 20x^12 10x^12  7x^12 = 1) same as above, I don't know if you need me to go a lil deeper or what not. x^12 ( 7x^3) (2x^6 )= here you do this: multiply both number cause they have only 1 variable / term in there ( a.k.a no constant or whatever) so 7*2 = 14 and x^3*x^6 is x^6+3 therefore 14x^9 (18x^13 ) divided by ( 3x^7 ) here you don't have to use Euclidean division again as above because it ISNT a POLYNOMIAL so youd have 18x^13/3x^7 do this: 18/7 (keep it in its simplest form which is that due to 7 being a prime number if thats how you say it in english) and x^13/x^7 is x^137 therefore x^6 so your answer would be 18/7 x^6

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0Hope I helped you :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.