anonymous
  • anonymous
Simplify.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[x{3} + 8 x{3}\]
across
  • across
\[x^3+8x^3=x^3(1+8)=9x^3\]
anonymous
  • anonymous
Cool! Here's the next one...\[15x{7}-13x{7}\]

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across
  • across
Could you do the same exact thing for this one?
mayankdevnani
  • mayankdevnani
x^7(15-13)=2x^7
mayankdevnani
  • mayankdevnani
@HorseCrazyGirlForever ok
anonymous
  • anonymous
\[2x{7}\]
anonymous
  • anonymous
( x^5) (3x^5)
mayankdevnani
  • mayankdevnani
yaa
anonymous
  • anonymous
What is the answer?
mayankdevnani
  • mayankdevnani
x^5*3x^5 3x^5
anonymous
  • anonymous
Cool! Here's the next one........
anonymous
  • anonymous
(3x^8) divided by ( x^5 )
mayankdevnani
  • mayankdevnani
x^5(3x^3) 3x^8
anonymous
  • anonymous
Awesomeness! Here are all the rest. 5x^3+9x^3-7x^3 = 20x^12 -10x^12 - 7x^12 = ( 7x^3) (2x^6 )= (18x^13 ) divided by ( 3x^7 )
myininaya
  • myininaya
Hey! @HorseCrazyGirlForever you should be wanting to learn this. Ask questions and engage in the discussion. @mayankdevnani If the user is asking similar questions, make them do a little more work each time. Try to teach. And also please make a separate thread for each question. Thanks.
anonymous
  • anonymous
You don't even need to factor our the x... they have the same base so you can add / substract them.... Then you go by factoring. --> simplify if you have different bases and then factor out stuff to get to your simplest form.
mayankdevnani
  • mayankdevnani
ok
mayankdevnani
  • mayankdevnani
thnx @myininaya
anonymous
  • anonymous
I don't really understand...
anonymous
  • anonymous
which one?
anonymous
  • anonymous
The ones I just posted.......
anonymous
  • anonymous
I am assuming all of them are different equations btw 5x^3+9x^3-7x^3 = 1) Simplify them by adding / substracting because of same base 7x^3 20x^12 -10x^12 - 7x^12 = 1) same as above, I don't know if you need me to go a lil deeper or what not. x^12 ( 7x^3) (2x^6 )= here you do this: multiply both number cause they have only 1 variable / term in there ( a.k.a no constant or whatever) so 7*2 = 14 and x^3*x^6 is x^6+3 therefore 14x^9 (18x^13 ) divided by ( 3x^7 ) here you don't have to use Euclidean division again as above because it ISNT a POLYNOMIAL so youd have 18x^13/3x^7 do this: 18/7 (keep it in its simplest form which is that due to 7 being a prime number if thats how you say it in english) and x^13/x^7 is x^13-7 therefore x^6 so your answer would be 18/7 x^6
anonymous
  • anonymous
Hope I helped you :)

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