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Karyatou
Group Title
The first three terms of a sequence are given.
15,10,20/3,...
Find the 6th term.
 2 years ago
 2 years ago
Karyatou Group Title
The first three terms of a sequence are given. 15,10,20/3,... Find the 6th term.
 2 years ago
 2 years ago

This Question is Closed

across Group TitleBest ResponseYou've already chosen the best response.0
Let \(a_0=15\). Then\[a_{n+1}=\frac{2a_n}{3}\qquad n=0,1,\dots\]
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
Here, you're looking for \(a_5\).
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
That is,\[a_5=(2/3)(2/3)(2/3)(2/3)(2/3)a_0=\frac{32}{243}a_0=\frac{480}{243}\approx1.975308641975309.\]
 2 years ago
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