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0!!!!

definitely \(\pi\)

what is your evidence @satellite73

oh wait, i am wrong it is \(e^2\) sorry

assuming of course these are functions...

there is another way

really? hmm

change infinity to 1/0 to make it 0/0?

either way...it's indeterminate....

so it could be \(\pi\) or it could be \(e^2\) or it could be anything

just expressing how weird math is

not at all

infinity is not a number, and so \(\frac{1}{\infty}\) is not a number either

|dw:1349968485543:dw|

math is still weird....

i never really understood the function of limits...

math is too ambiguous for me

\(\infty\) is not a number
\(\infty\times 0\) is not a number
\[\frac{5}{\infty}\] is not a number

(aside: Anybody hear the full treatment of 'Hilbert's Hotel?')

Is the slope of the vertical line +∞ or -∞ @UnkleRhaukus ?

i dont know what 'Hilbert's Hotel?' is

the product of the slopes of perpendicular lines is

Yes, but what is the slope of the vertical line?

\[\pm\infty\]

this might help

infinity is stupid. \[\infty + 1 = \infty \]
\[1 = \infty - \infty = 0\]

\[\infty\times 0=-1\]

\[\large 2 \times ∞ \times 0 = -2?\]