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UnkleRhaukus Group Title

\[\infty\times0=\]

  • 2 years ago
  • 2 years ago

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  1. Fox375 Group Title
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    0!!!!

    • 2 years ago
  2. UnkleRhaukus Group Title
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    @lgbasallote

    • 2 years ago
  3. theredhead1617 Group Title
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    0

    • 2 years ago
  4. satellite73 Group Title
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    definitely \(\pi\)

    • 2 years ago
  5. Fox375 Group Title
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    @satellite73 IKR

    • 2 years ago
  6. UnkleRhaukus Group Title
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    what is your evidence @satellite73

    • 2 years ago
  7. satellite73 Group Title
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    oh wait, i am wrong it is \(e^2\) sorry

    • 2 years ago
  8. lgbasallote Group Title
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    you can rewrite \[\infty \times 0\] as \[\infty \times \frac 1\infty\] right? then it becomes l'hospital...

    • 2 years ago
  9. lgbasallote Group Title
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    assuming of course these are functions...

    • 2 years ago
  10. UnkleRhaukus Group Title
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    there is another way

    • 2 years ago
  11. lgbasallote Group Title
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    really? hmm

    • 2 years ago
  12. lgbasallote Group Title
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    change infinity to 1/0 to make it 0/0?

    • 2 years ago
  13. lgbasallote Group Title
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    either way...it's indeterminate....

    • 2 years ago
  14. satellite73 Group Title
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    if this is a serious question, presumably it is about limits, i.e. if \(\lim_{x\to\infty}f(x)=\infty\) and \(\lim_{x\to \infty}g(x)=0\) then what is \[\lim_{x\to \infty}f(x)g(x)\] the answer is it could be anything, it depends on \(f\) and \(g\) the form is not determined

    • 2 years ago
  15. CliffSedge Group Title
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    \[\large a \times b = c\] \[\large a=\frac{c}{b}\] \[\large b=\frac{c}{a}\] Let a = ∞, b=0 \[\large ∞=\frac{c}{0}\] \[\large 0=\frac{c}{∞}\] But c/0 is undefined and so is c/∞, right? What if c were positive? What if c were negative?

    • 2 years ago
  16. satellite73 Group Title
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    so it could be \(\pi\) or it could be \(e^2\) or it could be anything

    • 2 years ago
  17. lgbasallote Group Title
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    an interesting question though is... \[\frac 1 \infty = 0\] therefore... \[0 \times \infty = 1\] that should be right?

    • 2 years ago
  18. lgbasallote Group Title
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    just expressing how weird math is

    • 2 years ago
  19. satellite73 Group Title
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    not at all

    • 2 years ago
  20. satellite73 Group Title
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    infinity is not a number, and so \(\frac{1}{\infty}\) is not a number either

    • 2 years ago
  21. CliffSedge Group Title
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    Agree with @satellite73 To say that 1/∞ = 0, you have to take the limit of 1/x as x-->∞ and then 0 × (x is really really big) still equals 0.

    • 2 years ago
  22. UnkleRhaukus Group Title
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    |dw:1349968485543:dw|

    • 2 years ago
  23. lgbasallote Group Title
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    math is still weird....

    • 2 years ago
  24. CliffSedge Group Title
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    (I'm going to have to go get coffee, then come back for this. Unkle is about to get all Twilight Zone on us, I can feel it.)

    • 2 years ago
  25. satellite73 Group Title
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    you are making short cut statements about limits namely if \[\lim_{x\to\infty}f(x)=\infty\] then \[\lim_{x\to \infty}\frac{1}{f(x)}=0\]

    • 2 years ago
  26. lgbasallote Group Title
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    i never really understood the function of limits...

    • 2 years ago
  27. lgbasallote Group Title
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    math is too ambiguous for me

    • 2 years ago
  28. satellite73 Group Title
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    \(\infty\) is not a number \(\infty\times 0\) is not a number \[\frac{5}{\infty}\] is not a number

    • 2 years ago
  29. CliffSedge Group Title
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    (aside: Anybody hear the full treatment of 'Hilbert's Hotel?')

    • 2 years ago
  30. CliffSedge Group Title
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    Is the slope of the vertical line +∞ or -∞ @UnkleRhaukus ?

    • 2 years ago
  31. UnkleRhaukus Group Title
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    i dont know what 'Hilbert's Hotel?' is

    • 2 years ago
  32. CliffSedge Group Title
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    Check it out some time. David Deutsch gives a good telling of it in his book, 'The Beginning of Infinity.' (Fantastic book on the philosophy of science; I recommend it to everyone.)

    • 2 years ago
  33. UnkleRhaukus Group Title
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    the product of the slopes of perpendicular lines is

    • 2 years ago
  34. CliffSedge Group Title
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    Yes, but what is the slope of the vertical line?

    • 2 years ago
  35. UnkleRhaukus Group Title
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    \[\pm\infty\]

    • 2 years ago
  36. helder_edwin Group Title
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    this might help

    • 2 years ago
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  37. JamesWolf Group Title
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    infinity is stupid. \[\infty + 1 = \infty \] \[1 = \infty - \infty = 0\]

    • 2 years ago
  38. UnkleRhaukus Group Title
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    \[\infty\times 0=-1\]

    • 2 years ago
  39. JamesWolf Group Title
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    all the even numbers = \[\infty\] which is smaller than all the numbers = \[\infty\] so \[\infty < \infty\]

    • 2 years ago
  40. CliffSedge Group Title
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    \[\large 2 \times ∞ \times 0 = -2?\]

    • 2 years ago
  41. CliffSedge Group Title
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    @JamesWolf there are different cardinalities of infinity. Research "Aleph Numbers" for more info. The infinity of integers is less than the infinity of real numbers, etc.

    • 2 years ago
  42. Jemurray3 Group Title
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    The bastardization of mathematics that has taken place in this thread is like salt rubbed into a fresh wound of my soul. Is there a legitimate question, or are you guys just playing around? :)

    • 2 years ago
  43. 03453660 Group Title
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    this is definitely an undefined case because any number multiplied with zero become zero and any number multiplied with infinity become infinity that's why both of these cases are possible here therefore we cannot consider one these case separately. thus this is an undefined case.

    • 2 years ago
  44. CliffSedge Group Title
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    @Jemurray3 I don't think there's anything serious going on. Unkle came up with a cute link to slopes of parallel lines, but made the error in saying that vertical lines have a slope, m=∞, which, of course, is false.

    • 2 years ago
  45. Coolsector Group Title
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    if the question is something like lim x->inf of 0*x then it is 0 otherwise we should be more specific about the problem i guess

    • 2 years ago
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