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UnkleRhaukus
 4 years ago
\[\infty\times0=\]
UnkleRhaukus
 4 years ago
\[\infty\times0=\]

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UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0what is your evidence @satellite73

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh wait, i am wrong it is \(e^2\) sorry

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2you can rewrite \[\infty \times 0\] as \[\infty \times \frac 1\infty\] right? then it becomes l'hospital...

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2assuming of course these are functions...

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0there is another way

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2change infinity to 1/0 to make it 0/0?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2either way...it's indeterminate....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if this is a serious question, presumably it is about limits, i.e. if \(\lim_{x\to\infty}f(x)=\infty\) and \(\lim_{x\to \infty}g(x)=0\) then what is \[\lim_{x\to \infty}f(x)g(x)\] the answer is it could be anything, it depends on \(f\) and \(g\) the form is not determined

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large a \times b = c\] \[\large a=\frac{c}{b}\] \[\large b=\frac{c}{a}\] Let a = ∞, b=0 \[\large ∞=\frac{c}{0}\] \[\large 0=\frac{c}{∞}\] But c/0 is undefined and so is c/∞, right? What if c were positive? What if c were negative?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it could be \(\pi\) or it could be \(e^2\) or it could be anything

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2an interesting question though is... \[\frac 1 \infty = 0\] therefore... \[0 \times \infty = 1\] that should be right?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2just expressing how weird math is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0infinity is not a number, and so \(\frac{1}{\infty}\) is not a number either

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Agree with @satellite73 To say that 1/∞ = 0, you have to take the limit of 1/x as x>∞ and then 0 × (x is really really big) still equals 0.

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349968485543:dw

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2math is still weird....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(I'm going to have to go get coffee, then come back for this. Unkle is about to get all Twilight Zone on us, I can feel it.)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are making short cut statements about limits namely if \[\lim_{x\to\infty}f(x)=\infty\] then \[\lim_{x\to \infty}\frac{1}{f(x)}=0\]

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2i never really understood the function of limits...

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.2math is too ambiguous for me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(\infty\) is not a number \(\infty\times 0\) is not a number \[\frac{5}{\infty}\] is not a number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(aside: Anybody hear the full treatment of 'Hilbert's Hotel?')

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is the slope of the vertical line +∞ or ∞ @UnkleRhaukus ?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0i dont know what 'Hilbert's Hotel?' is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Check it out some time. David Deutsch gives a good telling of it in his book, 'The Beginning of Infinity.' (Fantastic book on the philosophy of science; I recommend it to everyone.)

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0the product of the slopes of perpendicular lines is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, but what is the slope of the vertical line?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0infinity is stupid. \[\infty + 1 = \infty \] \[1 = \infty  \infty = 0\]

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0\[\infty\times 0=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all the even numbers = \[\infty\] which is smaller than all the numbers = \[\infty\] so \[\infty < \infty\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large 2 \times ∞ \times 0 = 2?\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@JamesWolf there are different cardinalities of infinity. Research "Aleph Numbers" for more info. The infinity of integers is less than the infinity of real numbers, etc.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The bastardization of mathematics that has taken place in this thread is like salt rubbed into a fresh wound of my soul. Is there a legitimate question, or are you guys just playing around? :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is definitely an undefined case because any number multiplied with zero become zero and any number multiplied with infinity become infinity that's why both of these cases are possible here therefore we cannot consider one these case separately. thus this is an undefined case.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Jemurray3 I don't think there's anything serious going on. Unkle came up with a cute link to slopes of parallel lines, but made the error in saying that vertical lines have a slope, m=∞, which, of course, is false.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if the question is something like lim x>inf of 0*x then it is 0 otherwise we should be more specific about the problem i guess
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