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satellite73Best ResponseYou've already chosen the best response.2
definitely \(\pi\)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
what is your evidence @satellite73
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
oh wait, i am wrong it is \(e^2\) sorry
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
you can rewrite \[\infty \times 0\] as \[\infty \times \frac 1\infty\] right? then it becomes l'hospital...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
assuming of course these are functions...
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
there is another way
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
change infinity to 1/0 to make it 0/0?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
either way...it's indeterminate....
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
if this is a serious question, presumably it is about limits, i.e. if \(\lim_{x\to\infty}f(x)=\infty\) and \(\lim_{x\to \infty}g(x)=0\) then what is \[\lim_{x\to \infty}f(x)g(x)\] the answer is it could be anything, it depends on \(f\) and \(g\) the form is not determined
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
\[\large a \times b = c\] \[\large a=\frac{c}{b}\] \[\large b=\frac{c}{a}\] Let a = ∞, b=0 \[\large ∞=\frac{c}{0}\] \[\large 0=\frac{c}{∞}\] But c/0 is undefined and so is c/∞, right? What if c were positive? What if c were negative?
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
so it could be \(\pi\) or it could be \(e^2\) or it could be anything
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
an interesting question though is... \[\frac 1 \infty = 0\] therefore... \[0 \times \infty = 1\] that should be right?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
just expressing how weird math is
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
infinity is not a number, and so \(\frac{1}{\infty}\) is not a number either
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Agree with @satellite73 To say that 1/∞ = 0, you have to take the limit of 1/x as x>∞ and then 0 × (x is really really big) still equals 0.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1349968485543:dw
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
math is still weird....
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
(I'm going to have to go get coffee, then come back for this. Unkle is about to get all Twilight Zone on us, I can feel it.)
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
you are making short cut statements about limits namely if \[\lim_{x\to\infty}f(x)=\infty\] then \[\lim_{x\to \infty}\frac{1}{f(x)}=0\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
i never really understood the function of limits...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
math is too ambiguous for me
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
\(\infty\) is not a number \(\infty\times 0\) is not a number \[\frac{5}{\infty}\] is not a number
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
(aside: Anybody hear the full treatment of 'Hilbert's Hotel?')
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Is the slope of the vertical line +∞ or ∞ @UnkleRhaukus ?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
i dont know what 'Hilbert's Hotel?' is
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Check it out some time. David Deutsch gives a good telling of it in his book, 'The Beginning of Infinity.' (Fantastic book on the philosophy of science; I recommend it to everyone.)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
the product of the slopes of perpendicular lines is
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Yes, but what is the slope of the vertical line?
 one year ago

JamesWolfBest ResponseYou've already chosen the best response.0
infinity is stupid. \[\infty + 1 = \infty \] \[1 = \infty  \infty = 0\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\infty\times 0=1\]
 one year ago

JamesWolfBest ResponseYou've already chosen the best response.0
all the even numbers = \[\infty\] which is smaller than all the numbers = \[\infty\] so \[\infty < \infty\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
\[\large 2 \times ∞ \times 0 = 2?\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
@JamesWolf there are different cardinalities of infinity. Research "Aleph Numbers" for more info. The infinity of integers is less than the infinity of real numbers, etc.
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
The bastardization of mathematics that has taken place in this thread is like salt rubbed into a fresh wound of my soul. Is there a legitimate question, or are you guys just playing around? :)
 one year ago

03453660Best ResponseYou've already chosen the best response.0
this is definitely an undefined case because any number multiplied with zero become zero and any number multiplied with infinity become infinity that's why both of these cases are possible here therefore we cannot consider one these case separately. thus this is an undefined case.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
@Jemurray3 I don't think there's anything serious going on. Unkle came up with a cute link to slopes of parallel lines, but made the error in saying that vertical lines have a slope, m=∞, which, of course, is false.
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
if the question is something like lim x>inf of 0*x then it is 0 otherwise we should be more specific about the problem i guess
 one year ago
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