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bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.1x*2yy'+y^2 + 4xy' + 4y = 0 x*2yy'+4xy' = (4y+y^2) y'(2xy+4x)=(4y+y^2)

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.1y'=dy/dx = y(4+y)/[2x(y+2)]

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.1check the arithmetic

sharrisf
 2 years ago
Best ResponseYou've already chosen the best response.0I'm a little confused what are the * for?

Omniscience
 2 years ago
Best ResponseYou've already chosen the best response.0darn it im too slow :(\[\frac{d}{dx} \left(xy^{2}\right) +\frac{d}{dx} \left(4xy\right) =\frac{d}{dx} \left(10\right) => x2yy' +y^2 + 4xy'+y =0\]

Omniscience
 2 years ago
Best ResponseYou've already chosen the best response.0you use the product rule

sharrisf
 2 years ago
Best ResponseYou've already chosen the best response.0I'm wretched at caluculus. Thank you so much
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