anonymous
  • anonymous
xy^2+4xy=10 find dy/dx
Mathematics
jamiebookeater
  • jamiebookeater
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bahrom7893
  • bahrom7893
x*2yy'+y^2 + 4xy' + 4y = 0 x*2yy'+4xy' = -(4y+y^2) y'(2xy+4x)=-(4y+y^2)
bahrom7893
  • bahrom7893
y'=dy/dx = -y(4+y)/[2x(y+2)]
bahrom7893
  • bahrom7893
check the arithmetic

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anonymous
  • anonymous
I'm a little confused what are the * for?
anonymous
  • anonymous
darn it im too slow :(\[\frac{d}{dx} \left(xy^{2}\right) +\frac{d}{dx} \left(4xy\right) =\frac{d}{dx} \left(10\right) => x2yy' +y^2 + 4xy'+y =0\]
anonymous
  • anonymous
you use the product rule
bahrom7893
  • bahrom7893
* means times
anonymous
  • anonymous
I'm wretched at caluculus. Thank you so much

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