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sharrisf

xy^2+4xy=10 find dy/dx

  • one year ago
  • one year ago

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  1. bahrom7893
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    x*2yy'+y^2 + 4xy' + 4y = 0 x*2yy'+4xy' = -(4y+y^2) y'(2xy+4x)=-(4y+y^2)

    • one year ago
  2. bahrom7893
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    y'=dy/dx = -y(4+y)/[2x(y+2)]

    • one year ago
  3. bahrom7893
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    check the arithmetic

    • one year ago
  4. sharrisf
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    I'm a little confused what are the * for?

    • one year ago
  5. Omniscience
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    darn it im too slow :(\[\frac{d}{dx} \left(xy^{2}\right) +\frac{d}{dx} \left(4xy\right) =\frac{d}{dx} \left(10\right) => x2yy' +y^2 + 4xy'+y =0\]

    • one year ago
  6. Omniscience
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    you use the product rule

    • one year ago
  7. bahrom7893
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    * means times

    • one year ago
  8. sharrisf
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    I'm wretched at caluculus. Thank you so much

    • one year ago
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