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sasogeek
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\(\huge 3^x  2^{y+2}=49 \)
\(\huge 2^y  3^{x2}+1=0 \)
solve the system of equations.
 2 years ago
 2 years ago
sasogeek Group Title
\(\huge 3^x  2^{y+2}=49 \) \(\huge 2^y  3^{x2}+1=0 \) solve the system of equations.
 2 years ago
 2 years ago

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sasogeek Group TitleBest ResponseYou've already chosen the best response.0
i tried using logs but i got to a dead end... :/
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
try using a subtle substitution
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
\[a=3^x\]\[b=2^y\]
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
remember that \(2^{y+2}=2^2\times2^y=4\times2^y\)
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
ohhh, ok :) yeah...
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
This is why I love this site, I never would have known what to do there...
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
i know right, i'm helping a friend out but i'm stuck myself so thanks to you guys ;)
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
I agree  I have learnt SO MUCH from this site  it is truly amazing.
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
where's the button for "round of applause"?
 2 years ago

sasogeek Group TitleBest ResponseYou've already chosen the best response.0
thanks guys, we did it! xD \(\large x \approx 4.069 \) and \(\large y \approx 3.263\) can someone confirm this please... :)
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
hmmm  I actually get integer solutions
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.4
Using the substitutions I listed above, I get:\[a4b=49\tag{1}\]\[b\frac{a}{9}+1=0\tag{2}\]Multiplying (2) by 9 and moving the constant to the righthandside, we get:\[9ba=9\tag{3}\]Adding (1) and (3) gives:\[5b=40\implies b=8\]Substituting this into (1) gives:\[a=81\]Therefore:\[2^y=8\implies y=3\]\[3^x=81\implies x=4\]
 2 years ago
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