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\(\huge 3^x  2^{y+2}=49 \)
\(\huge 2^y  3^{x2}+1=0 \)
solve the system of equations.
 one year ago
 one year ago
\(\huge 3^x  2^{y+2}=49 \) \(\huge 2^y  3^{x2}+1=0 \) solve the system of equations.
 one year ago
 one year ago

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sasogeekBest ResponseYou've already chosen the best response.0
i tried using logs but i got to a dead end... :/
 one year ago

asnaseerBest ResponseYou've already chosen the best response.4
try using a subtle substitution
 one year ago

asnaseerBest ResponseYou've already chosen the best response.4
remember that \(2^{y+2}=2^2\times2^y=4\times2^y\)
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
This is why I love this site, I never would have known what to do there...
 one year ago

sasogeekBest ResponseYou've already chosen the best response.0
i know right, i'm helping a friend out but i'm stuck myself so thanks to you guys ;)
 one year ago

asnaseerBest ResponseYou've already chosen the best response.4
I agree  I have learnt SO MUCH from this site  it is truly amazing.
 one year ago

JakeV8Best ResponseYou've already chosen the best response.0
where's the button for "round of applause"?
 one year ago

sasogeekBest ResponseYou've already chosen the best response.0
thanks guys, we did it! xD \(\large x \approx 4.069 \) and \(\large y \approx 3.263\) can someone confirm this please... :)
 one year ago

asnaseerBest ResponseYou've already chosen the best response.4
hmmm  I actually get integer solutions
 one year ago

asnaseerBest ResponseYou've already chosen the best response.4
Using the substitutions I listed above, I get:\[a4b=49\tag{1}\]\[b\frac{a}{9}+1=0\tag{2}\]Multiplying (2) by 9 and moving the constant to the righthandside, we get:\[9ba=9\tag{3}\]Adding (1) and (3) gives:\[5b=40\implies b=8\]Substituting this into (1) gives:\[a=81\]Therefore:\[2^y=8\implies y=3\]\[3^x=81\implies x=4\]
 one year ago
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