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andreascott Group Title

Your computer-supply store sells two types of inkjet printers. The first, type A, costs $237 and you make a $22 profit on each one. The second, type B, costs $122 and you make a $19 profit on each one. You can order no more than 120 printers this month, and you need to make at least $2,400 profit on them. If you must order at least one of each type of printer, how many of each type of printer should you order if you want to minimize your cost? 69 of type A : 51 of type B 40 of type A : 80 of type B 51 of type A : 69 of type B 80 of type A : 40 of type B

  • 2 years ago
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    I could have sworn I helped you with this yesterday.

    • 2 years ago
  2. Hero Group Title
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    You can't say this one is different.

    • 2 years ago
  3. andreascott Group Title
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    I don't think you did? I don't remember having a problem like this ?

    • 2 years ago
  4. Hero Group Title
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    Hang on a minute.

    • 2 years ago
  5. andreascott Group Title
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    ok.

    • 2 years ago
  6. Hero Group Title
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    I don't know how you managed to delete those questions you posted yesterday.

    • 2 years ago
  7. andreascott Group Title
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    I didn't , I don't even know how to delete them ?

    • 2 years ago
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    If we let: a = number of type A computers b = number of type B computers Then we can produce the following equations: Amount of Computers a + b ≤ 120 Cost of Computers: C(a,b) = 237a + 122b Profit from computers: 22a + 19b ≥ 2400 So now we take the amount equation and the profit equation and solve for a and b: a + b ≤ 120 22a + 19b ≥ 2400 Multiply the first equation by 22 to get: 22a + 22b ≤ 2640 22a + 19b ≥ 2400 Isolate 22a in both equations: 22a ≤ 2640 - 22b 22a ≥ 2400 - 19b Now set: 22a ≤ 22a 2400 - 19b ≤ 2640 - 22b Place like terms on the same side: 22b - 19b ≤ 2640 - 2400 3b ≤ 240 b ≤ 240/3 b ≤ 80 Thus a ≤ 40 since we know that a + b ≤ 120

    • 2 years ago
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    That's the same solution I typed up yesterday.

    • 2 years ago
  10. Hero Group Title
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    That's why I was able to post it so quickly

    • 2 years ago
  11. Hero Group Title
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    Thus that proves the question was posted yesterday

    • 2 years ago
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    Furthermore, since a = 40 and b = 80, we can find the total cost: C(a,b) = 237a + 122b C(40,80) = 237(40) + 122(80) = 19,240

    • 2 years ago
  13. andreascott Group Title
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    I do remember that . But, I swear I didn't delete anything ? and so you mean to say my teacher gave me the same question for yesterday & today ? lol

    • 2 years ago
  14. Hero Group Title
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    After further review, it appears that someone else must have posted the same question.

    • 2 years ago
  15. Hero Group Title
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    An @MeganDarling

    • 2 years ago
  16. andreascott Group Title
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    oh , but is it even possible to delete questions you have asked ?

    • 2 years ago
  17. Hero Group Title
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    http://openstudy.com/users/megandarling#/users/megandarling/asked

    • 2 years ago
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    No, not anymore

    • 2 years ago
  19. Hero Group Title
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    However, it is possible to alter your question.

    • 2 years ago
  20. andreascott Group Title
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    Oh , well thank you for helping me again .

    • 2 years ago
  21. MeganDarling Group Title
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    hi? haha

    • 2 years ago
  22. andreascott Group Title
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    hey , lol . are you in connections acad. ?

    • 2 years ago
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