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andreascott
 3 years ago
Your computersupply store sells two types of inkjet printers. The first, type A, costs $237 and you make a $22 profit on each one. The second, type B, costs $122 and you make a $19 profit on each one. You can order no more than 120 printers this month, and you need to make at least $2,400 profit on them. If you must order at least one of each type of printer, how many of each type of printer should you order if you want to minimize your cost?
69 of type A : 51 of type B
40 of type A : 80 of type B
51 of type A : 69 of type B
80 of type A : 40 of type B
andreascott
 3 years ago
Your computersupply store sells two types of inkjet printers. The first, type A, costs $237 and you make a $22 profit on each one. The second, type B, costs $122 and you make a $19 profit on each one. You can order no more than 120 printers this month, and you need to make at least $2,400 profit on them. If you must order at least one of each type of printer, how many of each type of printer should you order if you want to minimize your cost? 69 of type A : 51 of type B 40 of type A : 80 of type B 51 of type A : 69 of type B 80 of type A : 40 of type B

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Hero
 3 years ago
Best ResponseYou've already chosen the best response.1I could have sworn I helped you with this yesterday.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1You can't say this one is different.

andreascott
 3 years ago
Best ResponseYou've already chosen the best response.0I don't think you did? I don't remember having a problem like this ?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1I don't know how you managed to delete those questions you posted yesterday.

andreascott
 3 years ago
Best ResponseYou've already chosen the best response.0I didn't , I don't even know how to delete them ?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1If we let: a = number of type A computers b = number of type B computers Then we can produce the following equations: Amount of Computers a + b ≤ 120 Cost of Computers: C(a,b) = 237a + 122b Profit from computers: 22a + 19b ≥ 2400 So now we take the amount equation and the profit equation and solve for a and b: a + b ≤ 120 22a + 19b ≥ 2400 Multiply the first equation by 22 to get: 22a + 22b ≤ 2640 22a + 19b ≥ 2400 Isolate 22a in both equations: 22a ≤ 2640  22b 22a ≥ 2400  19b Now set: 22a ≤ 22a 2400  19b ≤ 2640  22b Place like terms on the same side: 22b  19b ≤ 2640  2400 3b ≤ 240 b ≤ 240/3 b ≤ 80 Thus a ≤ 40 since we know that a + b ≤ 120

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1That's the same solution I typed up yesterday.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1That's why I was able to post it so quickly

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Thus that proves the question was posted yesterday

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Furthermore, since a = 40 and b = 80, we can find the total cost: C(a,b) = 237a + 122b C(40,80) = 237(40) + 122(80) = 19,240

andreascott
 3 years ago
Best ResponseYou've already chosen the best response.0I do remember that . But, I swear I didn't delete anything ? and so you mean to say my teacher gave me the same question for yesterday & today ? lol

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1After further review, it appears that someone else must have posted the same question.

andreascott
 3 years ago
Best ResponseYou've already chosen the best response.0oh , but is it even possible to delete questions you have asked ?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1http://openstudy.com/users/megandarling#/users/megandarling/asked

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1However, it is possible to alter your question.

andreascott
 3 years ago
Best ResponseYou've already chosen the best response.0Oh , well thank you for helping me again .

andreascott
 3 years ago
Best ResponseYou've already chosen the best response.0hey , lol . are you in connections acad. ?
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