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zordoloom

  • 3 years ago

Find a vector equation and parametric equations for the line segment that joins P(2, 0, 0) Q(6, 2, 2)

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  1. No-data
    • 3 years ago
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    Remember that to get vector equation you need any point that lies on to the line and a vector that goes in the same direction.

  2. No-data
    • 3 years ago
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    You could pick point P or point Q.

  3. across
    • 3 years ago
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    You could try\[\mathbf{r}(t)=\mathbf{P}+t(\mathbf{Q}-\mathbf{P}),\qquad0\leq t\leq1.\]Notice that if \(t=0\), then \(\mathbf{r}(t)=\mathbf{P}\), and if \(t=1\), then \(\mathbf{r}(t)=\mathbf{Q}\).

  4. No-data
    • 3 years ago
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    How do you make the letters bold @across ?

  5. zordoloom
    • 3 years ago
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    @across Do I just plug in the values P and Q for that formula?

  6. across
    • 3 years ago
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    \mathbf{}

  7. sami-21
    • 3 years ago
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    just write Large before you type

  8. No-data
    • 3 years ago
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    \[\vec{r}=\large{P}\]

  9. sami-21
    • 3 years ago
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    @zordoloom did you get it now ?

  10. zordoloom
    • 3 years ago
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    So the formula that across provided, Can I use that to find the equations?

  11. sami-21
    • 3 years ago
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    first find the required parallel vector to the line PQ=<6-2,2-0,2-0)= <4,2,2>

  12. sami-21
    • 3 years ago
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    yes you can use that .

  13. zordoloom
    • 3 years ago
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    so, i end up with r(t)=(2,0,0)+t(4,2,-2). Is this correct?

  14. sami-21
    • 3 years ago
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    r(t)=(2,0,0)+t(4,2,2 ) not -2 !!!

  15. zordoloom
    • 3 years ago
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    ok

  16. zordoloom
    • 3 years ago
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    Thanks!!

  17. sami-21
    • 3 years ago
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    welcome :)

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