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## anonymous 3 years ago Find a vector equation and parametric equations for the line segment that joins P(2, 0, 0) Q(6, 2, 2)

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1. anonymous

Remember that to get vector equation you need any point that lies on to the line and a vector that goes in the same direction.

2. anonymous

You could pick point P or point Q.

3. across

You could try$\mathbf{r}(t)=\mathbf{P}+t(\mathbf{Q}-\mathbf{P}),\qquad0\leq t\leq1.$Notice that if $$t=0$$, then $$\mathbf{r}(t)=\mathbf{P}$$, and if $$t=1$$, then $$\mathbf{r}(t)=\mathbf{Q}$$.

4. anonymous

How do you make the letters bold @across ?

5. anonymous

@across Do I just plug in the values P and Q for that formula?

6. across

\mathbf{}

7. anonymous

just write Large before you type

8. anonymous

$\vec{r}=\large{P}$

9. anonymous

@zordoloom did you get it now ?

10. anonymous

So the formula that across provided, Can I use that to find the equations?

11. anonymous

first find the required parallel vector to the line PQ=<6-2,2-0,2-0)= <4,2,2>

12. anonymous

yes you can use that .

13. anonymous

so, i end up with r(t)=(2,0,0)+t(4,2,-2). Is this correct?

14. anonymous

r(t)=(2,0,0)+t(4,2,2 ) not -2 !!!

15. anonymous

ok

16. anonymous

Thanks!!

17. anonymous

welcome :)

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