zordoloom
Find a vector equation and parametric equations for the line segment that joins P(2, 0, 0) Q(6, 2, 2)
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Remember that to get vector equation you need any point that lies on to the line and a vector that goes in the same direction.
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You could pick point P or point Q.
across
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You could try\[\mathbf{r}(t)=\mathbf{P}+t(\mathbf{Q}-\mathbf{P}),\qquad0\leq t\leq1.\]Notice that if \(t=0\), then \(\mathbf{r}(t)=\mathbf{P}\), and if \(t=1\), then \(\mathbf{r}(t)=\mathbf{Q}\).
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How do you make the letters bold @across ?
zordoloom
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@across Do I just plug in the values P and Q for that formula?
across
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\mathbf{}
sami-21
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just write Large before you type
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\[\vec{r}=\large{P}\]
sami-21
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@zordoloom did you get it now ?
zordoloom
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So the formula that across provided, Can I use that to find the equations?
sami-21
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first find the required parallel vector to the line
PQ=<6-2,2-0,2-0)= <4,2,2>
sami-21
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yes you can use that .
zordoloom
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so, i end up with r(t)=(2,0,0)+t(4,2,-2). Is this correct?
sami-21
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r(t)=(2,0,0)+t(4,2,2 ) not -2 !!!
zordoloom
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ok
zordoloom
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Thanks!!
sami-21
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welcome :)