anonymous
  • anonymous
Find a vector equation and parametric equations for the line segment that joins P(2, 0, 0) Q(6, 2, 2)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Remember that to get vector equation you need any point that lies on to the line and a vector that goes in the same direction.
anonymous
  • anonymous
You could pick point P or point Q.
across
  • across
You could try\[\mathbf{r}(t)=\mathbf{P}+t(\mathbf{Q}-\mathbf{P}),\qquad0\leq t\leq1.\]Notice that if \(t=0\), then \(\mathbf{r}(t)=\mathbf{P}\), and if \(t=1\), then \(\mathbf{r}(t)=\mathbf{Q}\).

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anonymous
  • anonymous
How do you make the letters bold @across ?
anonymous
  • anonymous
@across Do I just plug in the values P and Q for that formula?
across
  • across
\mathbf{}
anonymous
  • anonymous
just write Large before you type
anonymous
  • anonymous
\[\vec{r}=\large{P}\]
anonymous
  • anonymous
@zordoloom did you get it now ?
anonymous
  • anonymous
So the formula that across provided, Can I use that to find the equations?
anonymous
  • anonymous
first find the required parallel vector to the line PQ=<6-2,2-0,2-0)= <4,2,2>
anonymous
  • anonymous
yes you can use that .
anonymous
  • anonymous
so, i end up with r(t)=(2,0,0)+t(4,2,-2). Is this correct?
anonymous
  • anonymous
r(t)=(2,0,0)+t(4,2,2 ) not -2 !!!
anonymous
  • anonymous
ok
anonymous
  • anonymous
Thanks!!
anonymous
  • anonymous
welcome :)

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